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vovikov84 [41]
3 years ago
12

The nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calorie

s. How many calories does a hotdog actually have?
A. 1,000
B. It depends on how many hotdogs you eat
C. 100
D. 10
E. 100,000
Chemistry
1 answer:
Olenka [21]3 years ago
5 0

Answer:

C. 100

Explanation:

Biochemical researches and studies have found out that an average health hotdog has a calorie of between 100 and 150 which is usually dependent on the additives.

Since the nutrition label on the back of a package of hotdogs (purchased within the US) indicates that one hotdog contains 100 calories then it truly contains such amount of calories. The standard number of calories present in a hotdog is independent of the amount eaten by individuals.

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A certain first-order reaction has a rate constant of 2.75 10-2 s−1 at 20.°c. what is the value of k at 45°c if ea = 75.5 kj/mol
Gekata [30.6K]

Answer:

0.314 s⁻¹  

Step-by-step explanation:

Use the <em>Arrhenius equation.</em>

\ln( \frac{k_2 }{k_1 }) = (\frac{E_{a} }{R })(\frac{ 1}{T_1} - \frac{1 }{T_2 })\\

Data:

k₁ = 0.0275 s⁻¹;            k₂ = ?

Eₐ = 75.5 kJ·mol⁻¹

T₁ = 20 °C = 293.15 K; T₂ = 45°C = 318.15 K

<em>Calculation: </em>

\ln(\frac{k_{2} }{0.0275}) = (\frac{75 500 }{8.314})(\frac{ 1}{293.15} - \frac{1 }{318.15 })

\ln(\frac{k_{2} }{0.0275}) = 9081\times 2.681 \times10^{-4}

\ln(\frac{k_{2} }{0.0275}) = 2.434

\frac{k_{2} }{0.0275} = \text{e}^{2.434}

\frac{k_{2} }{0.0275} = 11.41

k₂ = 0.0275 × 11.41

k₂ = 0.314 s⁻¹

3 0
3 years ago
If the density of carbon tetrachloride is 0.893 g/mL, and a sample has a volume of 9.29 mL, what is the mass?
NNADVOKAT [17]

Answer:

8.3g

Explanation:

d=m/v

m=d*v

m=0.893*9.29

m=8.3g

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The sun causes water in the pond to evaporate
OLga [1]

Answer:

The answer is Radiation

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A sealed balloon occupies a volume of 250 mL at an unknown temperature. When the temperature is altered to 30 C, the balloon's v
Allushta [10]

Answer:

Initial temperature, T1 = 15°C

Explanation:

Given the following data;

Initial volume, V1 = 250 mL to Liters = 250/1000 = 0.25 L

Final temperature, T2 = 30°C

Final volume, V2 = 0.5 L

To find the initial temperature T1, we would use Charles' law.

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles is given by;

\frac {V}{T} = K

\frac{V1}{T1} = \frac{V2}{T2}

Making T1 the subject of formula, we have;

T_{1}= \frac{V_{1}}{V_{2}} * T_{2}

Substituting into the formula, we have;

T_{1}= \frac{0.25}{0.5} * 30

T_{1}= 0.5 * 30

<em>Initial temperature, T1 = 15°C</em>

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