1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N. Details about number of atoms can be found below.
How to calculate number of atoms?
The number of atoms of a substance can be calculated by multiplying the number of moles of the substance by Avogadro's number.
However, the number of moles of oxygen in glycine can be calculated using the following expression:
Molar mass of C₂H5O2N = 75.07g/mol
Mass of oxygen in glycine = 32g/mol
Hence; 32/75.07 × 7.51 = 3.2grams of oxygen in glycine
Moles of oxygen = 3.2g ÷ 16g/mol = 0.2moles
Number of atoms of oxygen = 0.2 × 6.02 × 10²³ = 1.205 × 10²³ atoms
Therefore, 1.205 × 10²³ atoms of oxygen will be present in 7.51 grams of glycine with formula C₂H5O2N.
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Answer:
two examples are blood and soapy water.
Explanation:
Answer:
24 mol Cu
General Formulas and Concepts:
<u>Chemistry</u>
Explanation:
<u>Step 1: Define</u>
RxN: 2Cu (s) + O₂ (g) → 2CuO (s)
Given: 12 moles O₂
<u>Step 2: Stoichiometry</u>
<u />
= 24 mol Cu
<u>Step 3: Check</u>
<em>We are given 2 sig figs.</em>
Our final answer is in 2 sig figs, so no need to round.
Answer:
CuSO4(aq)
Explanation:
The aqueous form of copper sulfate will conduct electricity.
The Solid form will not be a good conductor.
C₅H₁₂ will not conduct electricity
CO₂ will not conduct electricity
- Copper sulfate is an ionic compound
- In aqueous solutions or molten forms, ionic compounds can conduct an electric current using free mobile ions as carriers.
- This way, they are electrolytes.
- In solid state, the ions are arranged into a crystal lattice and will not conduct a current of electricity.
Explanation:
Chemical reaction equation for the give decomposition of
is as follows:.

And, initially only
is present.
The given data is as follows.
= 2.3 atm at equilibrium
= 0.69 atm
Therefore,

= 0.23 aatm
So,
= 2.3 - 2(0.23)
= 1.84 atm
Now, expression for
will be as follows.


= 
= 0.0224
or, 
Thus, we can conclude that the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture is
.