I would have each block be 1/6 of a yard
You could technically have any value you want, but for me 1/6 is easiest because 1/2 and 1/3 will scale up to this like so
1/2 = (1/2)*(3/3) = 3/6
1/3 = (1/3)*(2/2) = 2/6
The diagram below might help if you're still stuck on why I picked 1/6.
A good place to start is to set 
to y. That would mean we are looking for 
to be an integer. Clearly, 
, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since 
is a radical, it only outputs values from ![[0,\infty]](https://tex.z-dn.net/?f=%20%5B0%2C%5Cinfty%5D%20)
, which means y is on the closed interval: ![[0,120]](https://tex.z-dn.net/?f=%20%5B0%2C120%5D%20)
.
With that, we don't really have to consider y anymore, since we know the interval that is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:
Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
W = 1.414213562 (or 2 squared)
x = 2 (because the y gets cancelled out in the first equation)
y = 1 (since 2(1)=2(1))
tell me if i’m right :)
Hope this helps you understand
Answer:
The missing angle is 37.60 degrees.
Step-by-step explanation: 180-90-52.40=37.60
