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2 years ago

6

You leave a pile of sand in your backyard on a windy day. Every minute the wind blows away 10 percent of the remaining sand. You

started with five cubic feet of sand. What equation models the amount of sand after minutes?

1 answer:

Grace [21]2 years ago

8 0

Answer:

10% of the remaining sand
You had 5 ft of sand
So y=5(.10(x))

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Please show/explain how you found the answer

KATRIN_1 [288]

H=3.4s- start with the problem
20=3.4s- substitute the known number(s)
20/3.4=3.4/3.4 s- divide both sides by 3.4
The answer is about 5.88, your answer should be between 5 and 6

3 0

3 years ago

Im working with FOIL distribution system, and the distribution says that x times 2x= 2x^2. Why does it make it squared equation?

jek_recluse [69]

Answer:

No, let me explain

Step-by-step explanation:

The definition of squared is a value multiplied by itself, and in this case, 2x(x) x is being multiplied by itself. Keep in mind that x is a value, so it could be any number. We can't say that x times 2x equals 2x, because you are multiplying 2x by the value of x.

5 0

3 years ago

If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi

Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = $\mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2}$ --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and $\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

$\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16$

$34 \times 1+\frac{1}{2} \times a \times 1^{2}=18$

$34+\frac{a}{2}=18$

$\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}$

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0

3 years ago

A disc has a diameter of centimeters while a mini disc has a diameter of centimeters. Write the ratio of the mini disc diameter

Dafna1 [17]

Answer:

2 : 3

Step-by-step explanation:

A disc has a diameter of 21 cm while a mini disc has a diameter of 14cm. Write the ratio of the mini disc diameter to the disc diameter.

Answer: Let the diameter of the mini disc be $d_1$ while the diameter of the disc be $d_2$ . To get the ratio of the mini disc diameter to the disc diameter, we just simply have to divide the diameter of the mini disc by the diameter of the disc and then represent the fraction in ratio form. The ratio of the disc diameters is given by:

Ratio of the mini disc diameter to the disc diameter = Diameter of mini disc / diameter of disc

Ratio of the mini disc diameter to the disc diameter = $\frac{14}{21}=\frac{2}{3}$

Ratio of the mini disc diameter to the disc diameter = 2 : 3

3 0

3 years ago

The variable, y, varies directly with x. If y = 26 when x = 21,<br> what is y when x = 64?

STatiana [176]

Answer:

y=69

Step-by-step explanation:

first step:when y=26 and x=21

c=y-x

c=26-21

c=5

second step: when y is unknown and x=64

To find y we simply add the value of c to x

y=x+c

y=64+5

y=69

6 0

3 years ago