All categories

2 years ago

How do I graph the equation? y-5= -4(x -1)(Also in the photo)

Mathematics

2 answers:

Kisachek [45]2 years ago

8 0

Well if your finding the slope and y intercept
Slope is -4
Y-int is (0,9)
So you would make the. -4 into -4/1 the you would plot (0,9) on the graph first then on the Y line go down 4 and move to the right 1
( I’m not sure if this helps)

sammy [17]2 years ago

8 0

0,9 is the answer to the problem

You might be interested in

Identify the type of function represented by

SCORPION-xisa [38]

That's definitely an example of exponential decay, since the base (1/2) (also called the "common ratio") is greater than 0 but less than 1.

6 0

3 years ago

(a+2b)² ?????????????????????<br>

lbvjy [14]

Answer:

a² + 4ab + 4b²

Step-by-step explanation:

Given

(a + 2b)²

= (a + 2b)(a + 2b)

Each term in the second factor is multiplied by each term in the first factor, that is

a(a + 2b) + 2b(a + 2b) ← distribute both parenthesis

= a² + 2ab + 2ab + 4b² ← collect like terms

= a² + 4ab + 4b²

3 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x + 2}$ with x = 0: $y = \sqrt [3] {2}$ in the same way is defined.

Answer:

$y = \sqrt {x-2}$

Option b

6 0

3 years ago

Which of the following figures could represent the cross section of a rectangular pyramid? Select all that apply.

Rama09 [41]

Answer:

Options C and E

Step-by-step explanation:

Option A. Circle

We can't get a cross section in the form of a circle.

Option B. Cube

We can't get a cross section in the form of a cube.

Option C. Rectangle

When we slice a rectangular pyramid parallel to the base but not through the vertex, we get a Rectangle.

Option D. Square

We can not get a square by slicing a rectangular pyramid.

Option E. Triangle

By slicing a rectangular pyramid perpendicular to the base and passing through the vertex we can get the cross section in the form of triangle.

Options C and E will be the answer.

4 0

2 years ago

Miles is playing catch with his friend. He throws the baseball from point A to point B

MAXImum [283]

Answer:

1234567890

Step-by-step explanation:

1234567890

8 0

2 years ago

How do I graph the equation? y-5= -4(x -1)(Also in the photo)​

How do I graph the equation? y-5= -4(x -1)(Also in the photo)