All categories

3 years ago

How do I graph the equation? y-5= -4(x -1)(Also in the photo)

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

Well if your finding the slope and y intercept
Slope is -4
Y-int is (0,9)
So you would make the. -4 into -4/1 the you would plot (0,9) on the graph first then on the Y line go down 4 and move to the right 1
( I’m not sure if this helps)

sammy [17]3 years ago

8 0

0,9 is the answer to the problem

You might be interested in

7. There are approximately 1.2 x 108 households

Vikentia [17]

Answer:

the answer would be 35

Step-by-step explanation:

8 0

3 years ago

Vector u has its initial point at (-7,2) and it's terminal point at (11,-5). Vector v has a direction opposite that of vector u,

PSYCHO15rus [73]

Answer:

$3\vec{v} = ( - 21,54)$

Step-by-step explanation:

$\vec{u} = (18,- 7)\Rightarrow \vec{v} = ( - 7,18) \Rightarrow 3\vec{v} = ( - 21,54)$

8 0

3 years ago

5x^2-2x=2 help plsmmm

Yuki888 [10]

Answer:

Presumably you're solving for x here? Without further information we'll assume that.

With that in mind, x is approximately equal to 0.86 and -0.46

Step-by-step explanation:

Let's start by putting it in the usual ax² + bx + c format.

$5x^2- 2x = 2\\5x^2 - 2x - 2 = 0\\$

let's solve it. First we'll multiply both sides by five, making the first term a perfect square:

$25x^2 - 10x - 10 = 0\\$

Now we'll add 11 to both sides:

$25x^2 - 10x + 1 = 11\\$

Which makes the left side a perfect square:

$(5x - 1)^2 = 11$

And now we can solve for x:

$(5x - 1)^2 = 11\\\\5x - 1 = \sqrt{11} \\\\5x = 1 + \sqrt{11}\\\\x = \frac{1 + \sqrt{11}}{5}$

Note that there's no apparent way of drawing the ± symbol when editing equations, so take that + sign as actually being ±.

That gives us two answers:

$x = \frac{1 + \sqrt{11}}{5}\\\\x \approx \frac{1 + 3.32}5\\\\x \approx \frac{4.32}5\\\\x \approx 0.86$ $x = \frac{1 - \sqrt{11}}{5}\\\\x \approx \frac{1 - 3.32}5\\\\x \approx \frac{-2.32}5\\\\x \approx -0.46$

7 0

3 years ago

Just need the equation

Anna007 [38]

$a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

Each of the equations can be solved as shown below:

a. $3x + 7 = - x - 1$

$3x + 7 + x = - x - 1 + x$ (addition property of equality)

$4x + 7 = - 1\\4x + 7 - 7 = -1-7$ (Subtraction property of equality)

$4x = -8\\\frac{4x}{4} = \frac{-8}{4}$ (Division property of equality)

$x = -2$

b. $1 - 2x + 5 = 4x - 3\\$

Add like terms

$6 - 2x = 4x - 3\\\\6 - 2x - 6 = 4x - 3 - 6$ (Subtraction property of equality)

$- 2x = 4x - 9\\-2x - 4x = 4x -9 - 4x$ (Subtraction property of equality)

$-6x = -9 \\\frac{-6x}{-6} = \frac{-9}{-6}$ (Division property of equality)

$x = \frac{3}{2}$

c. $4x - 2 + x =-2 + 2x\\$

$5x - 2 = -2 + 2x\\5x - 2x = -2 + 2\\3x = 0\\ x = \frac{0}{3} \\x = 0$

d. $3x - 4 + 1 = - 2x -5 + 5x\\$

$3x - 3 = - 7x -5\\3x + 7x = 3 - 5\\10x = -2\\x = \frac{-2}{10} \\x = -\frac{1}{5}$

The value of x in each equation are:

$a. $ x = -2\\b. $ x = \frac{3}{2} \\c. $ x = 0\\d. $ x = -\frac{1}{5}$

Learn more here:

brainly.com/question/1527981

5 0

3 years ago

Need help on solving this ?

katovenus [111]

For the first question, simply plug in the value of 3 into the polynomial question. The final answer is your volume of the hot water tub.

For the second question, you can figure out that x = -5 is not a real root because it does not touch or cross the x axis.

If it does it would be an solution.

4 0

3 years ago

How do I graph the equation? y-5= -4(x -1)(Also in the photo)​

How do I graph the equation? y-5= -4(x -1)(Also in the photo)