Out of the total 60 students 18 take Algebra 1 and 20 take Algebra II. 10 take both. So out of the 18 taking algebra 10 are taking Algebra II. If we don't count that 10 because they are already counted in Algebra II count. So 28 students are taking either course. Therefore 60-28 = 32 students who are not taking either of these courses
Answer:
255
Step-by-step explanation:
10n^2+5
where n=5
10×5²+5
10×25+5
250+5
255
Answer:
(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20
(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20
Step-by-step explanation:
There are two inequalities in mind, the first of the surface and the second of the price. Always bearing in mind that the minimum are 50 of A and 20 of B.
The first
A occupies 1/2 m and B occupies 1/2 m of surface, and the limit is 100 m of surface. Thus:
(1/2) * A + (1/2) * B <= 100; for A => 50; for B => 20
The second:
A costs 5,000 and B costs 30,000, and the limit is 1,500,000. Therefore:
(5000) * A + (30000) * B <= 1500000; for A => 50; for B => 20
X = 10 So if is that all?
Answer:
210 I think
Step-by-step explanation:
2000 divided by 10 is 200
And the length was 10cm longer
It would be 210
I am not to sure, Please correct me if I am wrong.
