The top right is a function, because no point cross twice over the y axis
I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])
Answer:
Step-by-step explanation:
Simplify expression with rational exponents can look like a huge thing when you first see them with those fractions sitting up there in the exponent but let's remember our properties for dealing with exponents. We can apply those with fractions as well.
Examples
(a) 
From above, we have a power to a power, so, we can think of multiplying the exponents.
i.e.


Let's recall that when we are dealing with exponents that are fractions, we can simplify them just like normal fractions.
SO;


Let's take a look at another example

Here, we apply the
to both 27 and 


Let us recall that in the rational exponent, the denominator is the root and the numerator is the exponent of such a particular number.
∴
![= \Bigg (\sqrt[3]{27}^{5} \times x^{10} }\Bigg)](https://tex.z-dn.net/?f=%3D%20%5CBigg%20%28%5Csqrt%5B3%5D%7B27%7D%5E%7B5%7D%20%5Ctimes%20x%5E%7B10%7D%20%7D%5CBigg%29)


Answer:
60
Step-by-step explanation:
It is really easy just subtract the money with the percentage
Answer:
x = 8
Step-by-step explanation:
I think this is the answer if I am wrong please do not report me
I hope this helps! :}