Answer is 120.
(Sorry if photo quality is bad. The camera on my device sucks.)
Answer:
2
Step-by-step explanation:
loge(x) is ln(x)
f(x) × ln(x)
Differentiate using product law
[ln(x) × f'(x)] + [(1/x) × f(x)]
x = 1
[ln(1) × f'(1)] + [(1/1) × f(1)]
(0 × 4) + (1 × 2)
0 + 2
2
We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;
If u separate these into 2 triangles then they will become 90 degree triangles so angle a=angle c.