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ankoles [38]
4 years ago
12

What is the factorization of the trinomial below?x3 - 2x2 - 35x

Mathematics
1 answer:
Nat2105 [25]4 years ago
5 0
A. 

Start by factoring out an x and then you have a standard trinomial, which you can factor by examining the factors of the final number that add up to the middle number. 
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Help me please :( I cant seem to get it right
Kazeer [188]
31 is (1)

3 females out of 5 widowed students, 3/5 = 0.6 which is 60%.

the answer for 30 is 10/30 or 33.3%, which isn't an option
7 0
3 years ago
Please help, i already tried and couldn't get it right
yan [13]

Answer:

3072

Step-by-step explanation:

<u>General form of a geometric sequence</u>:

  a_n=ar^{n-1}

where:

  • a_n is the nth term
  • a is the first term
  • r is the common ratio

Given values:

  • first term, a = 3
  • common ratio, r = 4

Substitute the given values into the formula to create an <u>equation for the nth term</u>:

\implies a_n=3(4)^{n-1}

To find the 6th term, substitute n = 6 into the equation:

\implies a_6=3(4)^{6-1}

\implies a_6=3(4)^{5}

\implies a_6=3(1024)

\implies a_6=3072

Therefore, the 6th term of a geometric sequence whose 1st term is 3 and whose common ratio is 4 is 3072.

Learn more about geometric sequences here:

brainly.com/question/27783194

4 0
2 years ago
A cube had a volume of 1/512 cubic meter. What is the length of each side of the cube using the formula "volume=Length×Width×Hig
MrRa [10]

Answer:

The length of each side of the cube is \frac{1}{8}\ m

Step-by-step explanation:

we know that

The volume of a cube is equal to

V=LWH

but remember that in a cube

Length, width and height have the same value

so

Let

b-----> the length side of the cube

L=W=H=b

substitute in the formula

V=(b)(b)(b)=b^{3}

In this problem we have

V=\frac{1}{512}\ m^{3}

substitute and solve for b

b^{3}=\frac{1}{512}

b=\sqrt[3]{\frac{1}{512}}\\ \\b=\frac{1}{8}\ m

therefore

The length of each side of the cube is \frac{1}{8}\ m

4 0
4 years ago
An experiment on memory was performed, in which 16 subjects were randomly assigned to one of two groups, called "Sentences" or "
FromTheMoon [43]

Answer:

There is no significant difference between the averages.

Step-by-step explanation:

Let's call

\large X_{sentences} the mean of the “sentences” group

\large S_{sentences} the standard deviation of the “sentences” group

\large X_{intentional} the mean of the “intentional” group

\large S_{intentional} the standard deviation of the “intentional” group

Then, we can calculate by using the computer

\large X_{sentences}=28.75  

\large S_{sentences}=3.53553

\large X_{intentional}=31.625

\large S_{intentional}=1.40788

\large X_{sentences}-X_{intentional}=28.75-31.625=-2.875

The <em>standard error of the difference (of the means)</em> for a sample of size 8 is calculated with the formula

\large \sqrt{(S_{sentences})^2/8+(S_{intentional})^2/8}

So, the standard error of the difference is

\large \sqrt{(3.53553)^2/8+(1.40788)^2/8}=1.34546

<em>In order to see if there is a significant difference in the averages of the two groups, we compute the interval of confidence of  95% for the difference of the means corresponding to a level of significance of 0.05 (5%). </em>

<em>If this interval contains the zero, we can say there is no significant difference. </em>

<em>Since the sample size is small, we had better use the Student's t-distribution with 7 degrees of freedom (sample size-1), which is an approximation to the normal distribution N(0;1) for small samples. </em>

We get the \large t_{0.05} which is a value of t such that the area under the Student's t distribution  outside the interval \large [-t_{0.05}, +t_{0.05}] is less than 0.05.

That value can be obtained either by using a table or the computer and is found to be

\large t_{0.05}=2.365

Now we can compute our confidence interval

\large (X_{sentences}-X_{intentional}) \pm t_{0.05}*(standard \;error)=-2.875\pm 2.365*1.34546

and the confidence interval is

[-6.057, 0.307]

Since the interval does contain the zero, we can say there is no significant difference in these samples.

6 0
4 years ago
(-y+5×3)+(7.2y-9) <br> How do you solve tjis
dybincka [34]
First do the multiplication inside the parenthesis

(-y+15) + (7.2y-9)

Remove the parenthesis now

-y+15+7.2y-9

Simplify:

6.2y +6

So your final answer is \boxed{\sf{6.2y+6}}
4 0
3 years ago
Read 2 more answers
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