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3 years ago

Combine the like terms to create an equivalent expression. 4p+6−3

Mathematics

2 answers:

Veronika [31]3 years ago

8 0

Answer:

4p+3

Step-by-step explanation:

There are two different types of “categories/groups” in this expression: the p variable that’s being multiplied by 4, and the integers, 6 and -3. So you can combine the 6 and -3 (also 6 minus 3) which just gives you 3. All you have left is 4p+3. You can’t combine the 4p and 3 because they are different “categories/groups”.

Hope this helps and answers you question :)

Elden [556K]3 years ago

8 0

Answer:

♡ madeline here ♡

hi luv! its 4p+3

here are the steps.

number 1: 6-3=3

number 2: just take

the 4p and add it. easy.

stay safe and stay great. ☆

have a great day!

- madeline/madi

✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ

Step-by-step explanation:

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What is the reciprocal of 3 and 1/5

Vaselesa [24]

1/3 and 5 because 3/1 is three and 1/3 is the opposite while 1/5 is 5/1 which is 5.

4 0

3 years ago

Read 2 more answers

The vertices of a pentagon are located at (-5, 3).(-5, – 3),(4, -3).(0, 0), and (4, 3).

Anton [14]

24 units because you add it all up

7 0

3 years ago

I need help please

GREYUIT [131]

Answer:

Distance = 5 units

Step-by-step explanation:

The given problem asks us to determine the distance between two points, (1, 5) and (5, 2).

<h2>Solution:</h2>

In order to find the distance between two points, we can use the following distance formula:

$\displaystyle\mathsf{Distance\:(D)= \sqrt{(x_2\:-x_1)^2\:+\:(y_2\:-y_1)^2}}$

Let (x₁, y₁) = (1, 5)

(x₂, y₂) = (5, 2)

Step 1: Substitute points into the formula:

$\displaystyle\mathsf{Distance\:(D)= \sqrt{(x_2\:-x_1)^2\:+\:(y_2\:-y_1)^2}}$

$\displaystyle\mathsf{Distance\:(D)= \sqrt{(5\:-1)^2\:+\:(2\:-5)^2}}$

Step 2: Subtract the integers in each of the parenthesis under the radical:

$\displaystyle\mathsf{Distance\:(D)= \sqrt{(4)^2\:+\:(-3)^2}}$

Step 3: Evaluate the powers (exponents):

$\displaystyle\mathsf{Distance\:(D)= \sqrt{16\:+\:9}}$

Step 4: Add 16 and 9:

$\displaystyle\mathsf{Distance\:(D)= \sqrt{25}}$

Step 5: Take the square root of 25:

⇒ Distance (D) = 5 units.

<h2>Final Answer:</h2>

Therefore, the distance between points (1, 5) and (5, 2) is <u>5 units</u>.

<u><em>Keywords:</em></u>

Distance formula

Two points

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Learn more about about this topic here:

brainly.com/question/17119550

5 0

3 years ago

Please help me! I have this due at midnight and need answers! The first and good answer will get brainiest

Mumz [18]

Show the question we can’t see it

3 0

3 years ago

In the adjoining figure, area of trangle ABC is

Zepler [3.9K]

Answer:

$PQ=4\ cm$

Step-by-step explanation:

see the attached figure with the letter D to better understand the problem

we know that

The segment side AD is the height of triangle ABC

Triangles PBQ and ABD are similar by AA Similarity Theorem

The area of triangle ABC is equal to

$A=\frac{1}{2}(BC)(AD)$

we have

$A=48\ cm^2\\BC=12\ cm$

substitute

$48=\frac{1}{2}(12)(AD)$

$AD=8\ cm$

Remember that

If two triangles are similar then the ratio of its corresponding sides is proportional

$\frac{BP}{AB}=\frac{PQ}{AD}$

substitute the given values

$\frac{BP}{2BP}=\frac{PQ}{8}$

$\frac{1}{2}=\frac{PQ}{8}$

$PQ=4\ cm$

3 0

3 years ago