Answer: Our required probability is 0.044.
Step-by-step explanation:
Since we have given that
Number of customers who have entered the drawing = 17
Number of customers live in the town of Gaston = 5
Number of customers live in Pike = 4
Number of customers live in Wells = 8
The first customer will be selected and then second customer will be selected from the remaining .
Probability of getting first customers are Pike residents = 
Probability of getting second customers are Pike residents = 
So, the probability that both customers selected are Pike residents are

Hence, our required probability is 0.044.
Answer:
θ = π<em>n</em>
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Step-by-step explanation:
Answer:
5/2
Step-by-step explanation:
i hope this is the answer
Answer:
The 5th day must be 90
Step-by-step explanation:
The first 4 days averaged out to 80
You can find their total just by multiplying by 4. That won't tell you the exact values, but it will tell you their total when you add the 4 of them together.
80*4 = 320
Now you need to add another day into the mix. Call it x
320 + x
Now there are 5 days, not 4, and the new total is 82.
(320 + x) / 5 = 82 Multiply both sides by 5
5*(320 + x) / 5 = 82 *5
320 + x = 410 Subtract 320
-320 -320
x = 90
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days