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3 years ago

Please help me find the x and y intercept

Mathematics

1 answer:

Serhud [2]3 years ago

3 0

Answer:

x-intercept(s): (0,0)

y-intercept(s): (0,0)

Step-by-step explanation:

To find the x-intercept(s), substitute in 0 for y and solve for x

0 = -x

To find the y-intercept(s), substitute in 0 for x and solve for y

y = -(0)

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Please help! I will mark brainlist!

melamori03 [73]

Answer: A

Step-by-step explanation:

3 0

3 years ago

Points a,b and c are collinear and in that order. If AC=3x+3, AB=-1+2x, and Bc=11, find x and AC

zimovet [89]

The answers are:

AC = AB + BC

3x+3 = -1+2x+11

3x-2x = -1-3+11

x = 7

AC = 3x+3 x = 7

AC = 3x7+3

AC = 24

Hope it helps!

4 0

3 years ago

If a student randomly guesses at 20 multiple-choice questions, find the probability that the student gets exactly four correct.

ad-work [718]

Answer:

Probability = 0.190

Step-by-step explanation:

Given:

Number of questions, 'n' = 20

Each question has four choices.

Let event of choosing correct answer be success and its probability be represented by 'p'.

Therefore, event of choosing wrong answer is failure and its probability be represented by 'q'.

Now, probability of success is choosing one correct answer out of 4 options. So, $p=\frac{1}{4}=0.25$

Now, 'p' and 'q' are complements of each other. Therefore,

$q=1-p=1-0.25=0.75$

Now, we need 4 successes. Therefore, $x=4$

Using Bernoulli's theorem to find 'x' successes from 'n' questions, we get:

$P(x)=_{x}^{n}\textrm{C}p^xq^{n-x}$

Plug in 4 for 'x', 20 for 'n', 0.25 for 'p' and 0.75 for 'q'. Solve.

$P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{20-4}\\P(4)=_{4}^{20}\textrm{C}(0.25)^4(0.75)^{16}\\P(4)=4845\times (0.25)^4\times (0.65)^{16}\\\\P(4)=0.1896\approx0.190$

Therefore, the probability of getting 4 correct answers out of 20 questions is 0.190.

6 0

3 years ago

I don’t know how to solve this

g100num [7]

The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.

(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️

6 0

3 years ago

y varies jointly as x and z, and y = 32 m, x = 6 m, and z = 8 m. What is the value of y when x = 5 m and z = 12 m

Fantom [35]

We are given y = kxz
We also know 32 = k×6×8, so k = 32/48 = 2/3.
We are then asked to solve:

$y = \frac{2}{3} \times 5 \times 12 = 40$

3 0

3 years ago

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