Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
Answer:
The correct answer is: <em>B. blood cells would be in a hypotonic solution, so water would rush into the cell causing it to expand and eventually burst</em>.
Explanation:
Cells have a certain solute concentration that produces an osmotic pressure of aproximately 300 mOsm. For that reason, IVs solutions must have a solute concentration which equals the cell osmotic pressure. That is usually acomplished by using an aqueous solution of NaCl 0.9% w/v or 5% w/v Glucose.
If an IV of pure water is administrated to a person, the blood cells will be in a hypotonic solution. That is, with a concentration lesser than the concentration inside the cells. Due to the difference in concentration, a net flow of water will be produced from the exterior to the cell interior. As the volume of the cell is increased, the cell membrane is damaged and eventually the cell will collapse.
Answer:
<u><em>It is because humans have much larger genomes than bacteria</em></u>
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Explanation:
It is because humans have much larger genomes than bacteria. The largest bacterial genome ; human clocks. But corn is about 3 times that, spruce is twice again that and some plants go even bigger. For example, every one of tulip’s chromosomes is about one human genome in size, and bacteria are haploid, humans are diploid. That makes assembling the DNA fragments much more tricky, as you don’t want to have a final sequence that switches between the two haplotypes.
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<em>From a fellow student,</em>
<em>Good day ahead, :)</em>
<em>Dan</em>
The answer is D) carbon forms both single and double bonds.
