How can I write the formula for strontium fluoride?
1 answer:
First thing, you need to know what this molecule is made of.
The First atom is the Strontium Sr (For more information, used usually as a substitute of the calcium in the human body).
The Second Atom is made of 2 Fluoride F2 (because it chemical name is Strontium difluoride).
Then, you join them together and Get
And for more information, Strontium fluoride is usually used as an optical material.
Hope this Helps :)
The First atom is the Strontium Sr (For more information, used usually as a substitute of the calcium in the human body).
The Second Atom is made of 2 Fluoride F2 (because it chemical name is Strontium difluoride).
Then, you join them together and Get
And for more information, Strontium fluoride is usually used as an optical material.
Hope this Helps :)
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The naturally occurring isotopes of Li are Li-6 of mass 6.015121 amu and Li-7 of mass 7.016003 amu. The atomic mass of Li is 6.9409 amu, the percent abundance can be calculated using the following relation.
Atomic mass=m(Li-6 )×%(Li-6 )+m(Li-7 )×%(Li-7 )
Let the percent abundance of Li-6 be X thus, that of Li-7 will be 1-X, putting the values,
Or,
Or,
X=0.075
Thus,
Thus, percent abundance of Li-6 is 0.075 or 7.5 % and that of Li-7 is 0.925 or 92.5%.