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igor_vitrenko [27]
3 years ago
11

Calculate the volume of 12.0 g of helium at 100° C and 1.2 atm.

Chemistry
1 answer:
satela [25.4K]3 years ago
7 0

Answer:

the answer I think is 76.5L

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What is the half life of an atom that goes from 16000 g to 125 g in 163.24 days.
Alenkinab [10]

Answer:

23.32\ \text{days}

Explanation:

N = Final mass of atom = 125 g

N_0 = Initial mass of atom = 16000 g

t = Time taken = 163.24 days

t_{1/2} = Half life

We have the relation

N=N_0\dfrac{1}{2}^{\dfrac{t}{t_{1/2}}}\\\Rightarrow 125=16000\times \dfrac{1}{2}^{\dfrac{163.24}{t_{1/2}}}\\\Rightarrow \dfrac{125}{16000}=\dfrac{1}{2}^{\dfrac{163.24}{t_{1/2}}}\\\Rightarrow \ln0.0078125=\dfrac{163.24}{t_{1/2}}\ln0.5\\\Rightarrow t_{1/2}=\dfrac{163.24\times\ln0.5}{\ln0.0078125}\\\Rightarrow t_{1/2}=23.32\ \text{days}

The half life of the atom is 23.32\ \text{days}.

3 0
3 years ago
Find the number of moles of argon in 452 g of argon.
andrey2020 [161]

Answer: 13.31 moles.

Explanation: So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon.

6 0
3 years ago
A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/
galben [10]
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
   1.6 =12×C2
1.6/12=C2
C2     = 0.1333mg/mL
7 0
3 years ago
Read 2 more answers
50 POINTS!!!!!!
sattari [20]
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Distinguish between climate and atmosphere.
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What are you talking about and what’s the question
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