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Aneli [31]
3 years ago
8

Describe how an acidic solution forms when HCI is mixed in water

Chemistry
1 answer:
alekssr [168]3 years ago
6 0
Acids are solutions with a high concentration of H+ ions. When HCl is put into water it dissociates. That means it breaks apart by the reaction:
HCl —> H+ + Cl-
One of the products of dissociation is H+, making the solution Acidic.
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Write a balanced equation for the oxidation-reduction reaction that occurs when hydrogen peroxide reacts with ferrous ion
Alex17521 [72]
H₂O₂ + 2FeSO₄ + H₂SO₄ → Fe₂(SO₄)₃ + 2H₂O

H₂O₂ + 2H⁺ + 2e⁻ → 2H₂O  k=1
Fe²⁺ → Fe³⁺ + e⁻                 k=2

H₂O₂ + 2H⁺ + 2Fe²⁺ → 2H₂O + 2Fe³⁺


7 0
3 years ago
How much energy was lost in the total process illustrated? Please Help
7nadin3 [17]

Answer:

30%

Explanation:

I don't know how to explain but I learnt this yesterday

8 0
3 years ago
Read 2 more answers
What is the mass in grams of 6.12 x 10^20 molecules of caffeine, C8H10N4O2?
baherus [9]
6,02*10^{23} \ \ \ \ \ \ \rightarrow \ \ \ \ \ 194,2g\\
6,12 * 10^{20} \ \ \ \ \ \ \rightarrow \ \ \ \ \ x\\\\
x=\frac{6,12*10^{20}*194,2g}{6,02*10^{23}}\approx197*10^{-3}g=0,197g
6 0
3 years ago
Which heats up the fastest? treated glass, aluminum, stainless steel, or copper?
GrogVix [38]

Answer:

stainless steel

Explanation:

stainless steel would heat up fast because it is made of metal

8 0
2 years ago
What is the density of 0.50 grams of gaseous carbon stored under 1.5 atm of pressure at a temperature of -20.0 C?
Colt1911 [192]

Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.

Explanation:

  • d = m/V, where d is the density, m is the mass and V is the volume.
  • We have the mass m = 0.50 g, so we must get the volume V.
  • To get the volume of a gas, we apply the general gas law PV = nRT

P is the pressure in atm (P = 1.5 atm)

V is the volume in L (V = ??? L)

n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).

  • Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
  • Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
6 0
3 years ago
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