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kozerog [31]
3 years ago
9

Describe two ways in which humans have negatively affected groundwater.

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0

Answer: Stressors

Explanation:

it can deplete aquifers include changes in precipitation and snowmelt patterns

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Molecules in the gas phase move faster than the same molecules love in the liquid true or false
vredina [299]

true gas molicules bounce off one another much faster liquid just slides

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I need titration curve of sebacic acid
RoseWind [281]

Answer:

is a plot showing the change in ph of the solution in the conical flask as the reagent is added from the burette

Explanation:

like, the ph of the solution at equivalence point is dependent on the strenght of the acid and strenght of the base used in the titration

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Consider the reaction. 2 Al ( s ) + Fe 2 O 3 ( s ) heat −−→ Al 2 O 3 ( s ) + 2 Fe ( l ) If 17.3 kg Al reacts with an excess of F
IrinaVladis [17]

Answer:

32.7 kilograms of aluminium oxide  will be produced.

Explanation:

2 Al ( s ) + Fe_2O_3 ( s ) +heat\rightarrow Al_2O_3 ( s ) + 2 Fe ( l )

Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )

Moles of aluminium = \frac{17300 g}{27 g/mol}=640.74 mol

According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:

\frac{1}{2}\times 640.74 mol= 320.37 mol of aluminum oxide

Mass of 320.37 moles of aluminum oxides:

320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg

32.7 kilograms of aluminium oxide  will be produced.

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_______ is the application of scientific knowledge to solve problems or create new products.
astraxan [27]
Having resources? i guess... 
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At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
Leona [35]

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

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