All categories

2 years ago

Helppppppppppppppppppp

Mathematics

1 answer:

Thepotemich [5.8K]2 years ago

8 0

Answer:

vertical opposite angles are always equal

= 143°

co-interior angles are supplementary ( 180° )

∴ x = 180 - 143 = 37

∴ x = 37°

hope this answer helps you.....

please mark as brainliest.. thank you!

You might be interested in

Erik drives 19.2 miles in 16 minutes.

Katen [24]

Answer:

Erik's average speed exceeds the speed limit by 6.91 miles per hour.

Step-by-step explanation:

Let suppose that Erik travels at constant speed. Hence, the speed ( $v$ ), measured in miles per hour, is determined by following equation of motion:

$v = \frac{s}{t}$ (1)

Where:

$s$ - Distance, measured in miles.

$t$ - Time, measured in hours.

Please notice that a hour equals 60 minutes. If we know that $s = 19.2\,mi$ and $t = 0.267\,h$ , then the speed of Erik is:

$v = \frac{19.2\,mi}{0.267\,h}$

$v = 71.910\,\frac{mi}{h}$

Which is 6.91 miles per hour above the speed limit.

6 0

3 years ago

The area of a rectangle is 259 cm2 and its lenght is 18.5 cm find

crimeas [40]

The breadth of rectangle is 14 cm

The perimeter of rectangle is 65 cm

<em><u>Solution:</u></em>

Given that,

Area of rectangle = 259 square centimeter

Length of rectangle = 18.5 cm

<em><u>The area of rectangle is given by formula:</u></em>

$Area\ of\ rectangle = length \times breadth$

<h3><u>Find the breadth:</u></h3>

Substitute the given values in above formula:

$259 = 18.5 \times breadth\\\\breadth = \frac{259}{18.5}\\\\breadth = 14$

Thus breadth is 14 cm

<h3><u>Find the perimeter:</u></h3>

The perimeter of rectangle is given by formula:

$Perimeter = 2(length + breadth)$

Substitute the given values in above formula:

$perimeter = 2(18.5+14)\\\\perimeter = 2(32.5)\\\\perimeter = 65$

Thus perimeter of rectangle is 65 cm

7 0

2 years ago

What is the difference in simplest form? <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bn%5E2%2B3n%2B2%7D%7Bn%5E2%2B6n%2B8%7D-%5

Paha777 [63]

$\bf \cfrac{n^2+3n+2}{n^2+6n+8}-\cfrac{2n}{n+4}\implies \cfrac{n^2+3n+21}{(n+4)(n+2)}-\cfrac{2n}{n+4}
\\\\\\
\textit{so our LCD will just be (n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(n+2)(2n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~(2n^2+4n)}{(n+4)(n+2)}
\\\\\\
\cfrac{n^2+3n+2~~~~-~~~~2n^2-4n}{(n+4)(n+2)}
\implies 
\cfrac{-n^2-n+2}{(n+4)(n+2)}
\\\\\\
\cfrac{-(n^2+n-2)}{(n+4)(n+2)}\implies \cfrac{-\underline{(n+2)}(n-1)}{(n+4)\underline{(n+2)}}\implies \cfrac{-(n-1)}{n+4}\implies \cfrac{1+n}{n+4}$