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aliina [53]
3 years ago
8

A carpenter is building a bookcase of height h, length 2h, and width w. The bookcase has two shelves. The plywood to be used for

the back costs $1.50 per square foot. The top, bottom , sides, and shelves will be made of pine costing $5 per square foot. Write an equation expressing the total cost of the materials.
Enter your answer in the form: C = ahb + chw, where a, b, c are integers.
Mathematics
1 answer:
tresset_1 [31]3 years ago
6 0

Answer:

3h² + 35hw ;

a = 3 ; b = 2 ; c = 35

Step-by-step explanation:

Given that :

Dimension of bookcase :

Height = h ; Length = 2h ; width = w

Area of backside :

Height * length

h * 2h = 2h²

Cos of back material = $1.5 per ft²

Cost = 1.5 * 2h²

Cost = 3h²

Top and bottom :

Length * width

2h * w

Side area = 3 * h * w

Total area : Top + bottom +. Side

Total area : 2hw + 2hw + 3hw = 7hw

Pine = $5 per sq foot

Total cost = $5 * 7hw

= $35hw

Entire cost, C

3h² + 35hw

From the format :

ah^b + chw,

a = 3 ; b = 2 ; c = 35

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Answer

7^4

7 to the fourth power

7∙7∙7∙7

Step-by-step explanation

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5 0
3 years ago
Plz with steps .. it's very hard can anyone plz
liubo4ka [24]

Answer:

Step-by-step explanation:

\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a}  \qquad  f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a}  \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\  \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}}  }{\dfrac{1}{2\sqrt{x}} }\\\\

\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}  =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\

7 0
3 years ago
Simplify -3y+2x-5y-7x
Sphinxa [80]
<h3><em><u>Simplify -3y+2x-5y-7x is:</u></em></h3><h3>-8y - 5x</h3>

<em><u>Solution:</u></em>

<em><u>Given that, we have to simplify</u></em>

-3y + 2x-5y-7x

We can simplify the above expression by combining the like terms

Like terms are terms that has same variable ( with same exponent) with same or different coefficient

From given,

-3y + 2x-5y-7x

Here, like terms are -3y and -5y

And 2x and -7x

Group the like terms

-3y-5y+2x-7x

Combine the like terms

-8y -5x

Thus the given expression is simplified

6 0
3 years ago
A polynomial function has a zero at x=3 which of the follwing expressions must be one factor of the polynomial. A. x + 3 b. 3x C
nexus9112 [7]
I think the correct answer from the choices listed above is option D. A polynomial function has a zero value at x=3 for the <span>expression where one factor is x-3. This factor when x=3 will always result to a zero value no matter what you multiply to it. Hope this answers the question.</span>
5 0
3 years ago
Read 2 more answers
A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following
kiruha [24]

Answer:

<em>After </em><em>47</em><em> days she will have more than 90 trillion pennies.</em>

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

1,2,4,8,16,32,.....

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

S_n=\dfrac{a(r^n-1)}{r-1}

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}

\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}

\Rightarrow 90\times 10^{12}\le 2^n-1

\Rightarrow 2^n\ge 90\times 10^{12}+1

\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)

\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)

\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}

\Rightarrow n \ge 46.4

\Rightarrow n\approx 47


8 0
3 years ago
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