In order to find b1 from your formula stated we need to do few calculations
A=hb1+hb2, as you wee I multiply h with both bases( b1 and b2)
I will subtract hb2 from both sides
hb1=A-hb2
now I will divide my new expression by h
b1=(A-hb2)/h
Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
Answer:
Hello!
1 on the left in vertical and 1 on the right is adjacent hope that helps.
Answer:
the answer is 15feet doo paa deee
Answer:
f(x) = 2x(x - 8)
f(x) = 2(x - 2)² - 8
Step-by-step explanation:
Let the equation of the quadratic function is,
f(x) = a(x - h)² + k
Here, (h, k) is the vertex of the function.
From the graph attached,
Vertex of the parabola → (2, -8)
Therefore, equation of the function will be,
f(x) = a(x - 2)² - 8
Since, the graph passes through origin (0, 0),
f(0) = a(0 - 2)² - 8
0 = 4a - 8
a = 2
Equation of the given parabola will be,
f(x) = 2(x - 2)² - 8
= 2(x² - 4x + 4) - 8
= 2x² - 8x + 8 - 8
= 2x² - 8x
= 2x(x - 8)
Therefore, factored form of the function will be,
f(x) = 2x(x - 8)
