Can someone help me ?

Out of every 240 containers of juice brought in a grocery store, 116 are orange juice. what fraction purchased is orange juice

Rzqust [24]

116/240 which simplifies to 29/60 by dividing 116/240 by 4/4.

6 0

4 years ago

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Deanna,Amy, and Pam pick the same number of peaches at an orchard. They each set their peaches in four equal piles with6 peaches

ozzi

6·4=24

if they want you to find out how many peaches all of them picked together, its 24·3

4 0

3 years ago

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$800 at 4.25% intrest for 6 years

Ilia_Sergeevich [38]

To solve this (assuming that you mean simple interest) you need to first know the formula for exponential growth witch is S(1+(-)I) $^{T}$ so with all of are numbers inputed it looks something like this 800(1+.0425) $^{6}$ because,
S=starting amount, I=interest rate, and T=Time (amount of time that goes by)
back to the equation it would equal 1027 (rounded to the nearest dollar)

Enjoy!=)

7 0

3 years ago

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PLEASE HELPPP

Y_Kistochka [10]

The function $f(x)=(x-2)^3+8$ is one-to-one and the inverse of $f(x)$ is $f^{-1} (x)=(x-8)^\frac{1}{3}+2$ .

A function is one-to-one if for $f(a)=f(b)$ , we show that $a=b$ .

$f(a)=(a-2)^3+8$

$f(b)=(b-2)^3+8$

Take $f(a)=f(b)$

$(a-2)^3+8=(b-2)^3+8$

$(a-2)^3=(b-2)^3$

Let $A=a-2$ and $B=b-2$

If $A^3=B^3$ , then $A=B$ .

So, $a-2=b-2$

$a=b$ .

So, the function is one-to-one.

For the inverse of $f(x)$ , replace $x$ with $y$ and solve for $y$ .

$x=(y-2)^3+8$

$(y-2)^3=x-8$

$y-2=(x-8)^\frac{1}{3}$

$y=(x-8)^\frac{1}{3}+2$

So, the inverse of $f(x)$ is $y=(x-8)^\frac{1}{3}+2$ .

Learn more about and inverse of a function here:

brainly.com/question/2541698?referrer=searchResults

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Clarge%5Cbegin%7Bbmatrix%7D%20%5Cbegin%7Barray%7D%20%7B%20l%20l%20%7D%20%7B%202%20%7D%20%

SVETLANKA909090 [29]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

$\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}$

$\begin{bmatrix} \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \end{bmatrix} \begin{bmatrix} \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { - 1 } & { 1 } & { 5 } \end{array} \end{bmatrix}$

In matrix multiplication, the number of columns in the 1st matrix is equal to the number of rows in the 2nd matrix.

$\left(\begin{matrix}2&3\\5&4\end{matrix}\right)\left(\begin{matrix}2&0&3\\-1&1&5\end{matrix}\right)$

Multiply each element of the 1st row of the 1st matrix by the corresponding element of the 1st column of the 2nd matrix. Then add these products to obtain the element in the 1st row, 1st column of the product matrix.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&&\\&&\end{matrix}\right)$

The remaining elements of the product matrix are found in the same way.

$\left(\begin{matrix}2\times 2+3\left(-1\right)&3&2\times 3+3\times 5\\5\times 2+4\left(-1\right)&4&5\times 3+4\times 5\end{matrix}\right)$

Simplify each element by multiplying the individual terms.

$\left(\begin{matrix}4-3&3&6+15\\10-4&4&15+20\end{matrix}\right)$

Now, sum each element of the matrix.

$\large\boxed{\boxed{\left(\begin{matrix}1&3&21\\6&4&35\end{matrix}\right) }}$

7 0

3 years ago