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ludmilkaskok [199]
2 years ago
13

The sidereal period of the moon around the Earth is 27.3 days. Suppose a satellite were placed in Earth orbit, halfway between E

arth's center and the moon's orbit. Use Kepler's third law to find the period of this satellite. (Just use T2/r3 = constant. No need for Earth's mass or the value of G.) days.
Physics
1 answer:
icang [17]2 years ago
7 0

Answer: 9.7 days

Explanation:

Applying Kepler's 3rd law, we can write the following proportion:

(Tm)² / (dem)³ = (Tsat)² / (dem/2)³

(As the satellite is placed in an orbit halfway between Erth's center and the moon's orbit).

Simplifyng common terms, and solving for Tsat, we have:

Tsat = √((27.3)²/8) = 9.7 days

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What the planet after Venus
Aleonysh [2.5K]

Mercury and Venus are therefore closer to each other most of the time. But Earth is the planet closest to Venus. And that's why from here on Earth, Venus looks so big and luminous. Venus is the brightest thing in the night sky after the sun and the moon.

4 0
3 years ago
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Heat energy moves:_______.
steposvetlana [31]

c) only from warmer areas to colder areas.

The second principle of thermodynamics states that heat can only flow from a hotter body to a cooler one. Specifically, Clausius statement says that is not possible for heat to move by itself from a lower temperature body to a higher temperature body.

3 0
3 years ago
A basketball player shoots toward a basket 5.3 m away and 3.0 m above the floor. If the ball is released 1.9 m above the floor a
Snezhnost [94]

Answer:

Vi = 8.28 m/s

Explanation:

This problem is related to the projectile motion.

As we know there are two components of motion associated with this, the horizontal component and vertical component.

The horizontal distance covered by the ball is

Vx*t = x

Vx*t = 5.3

Vx = 5.3/t  eq. 1

Also we know that

Vx = Vicos(60)

Vx = Vi*0.5  eq. 2

equate eq. 1 and eq. 2

5.3/t = Vi*0.5

5.3/0.5 = Vi*t

Vi*t = 10.6  eq. 3

The vertical distance is

Vy = y1 + Vyi*t - 0.5gt²

also we know that

Vyi = Visin(60)

Vyi = Vi*0.866

It is given that V1 = 1.9 m and and Vy = 3 m is the vertical distance

3 = 1.9 + Vi*0.866*t - 0.5gt²

3 = 1.9 + Vi*0.866*t - 0.5(9.8)t²

3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²

3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²

1.1 = 0.866(Vi*t) - 4.9t²

0.866(Vi*t) = 4.9t² + 1.1

substitute Vi*t = 10.6 in above equation

0.866(10.6) = 4.9t² + 1.1

9.18 = 4.9t² + 1.1

4.9t² = 8.08

t² = 8.08/4.9

t² = 1.648

t = 1.28 sec

Finally, initial speed can be found by substituting the value of t into eq. 3

Vi*t = 10.6

Vi = 10.6/t

Vi = 10.6/1.28

Vi = 8.28 m/s

8 0
3 years ago
Measurement conversions [metric to metric] 568 cm = m​
Trava [24]

Answer:

5.68 meters

Explanation:

hope this helps!

7 0
3 years ago
PHYSICSSS PLEASE HELP
Aleonysh [2.5K]

Answer:

1. 10.5 Kg

2. s/g

Explanation:

1. Determination of the mass of gasoline

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

The density of a substance is simply defined as the mass of the substance per unit volume of the substance. Mathematically, the density of a substance can be expressed as:

Density = mass / volume

With the above formula, we can obtain the mass of the gasoline as follow:

Density of gasoline = 0.7 Kg/L

Volume of gasoline = 15 L

Mass of gasoline =?

Density = mass / volume

0.7 = Mass of gasoline / 15

Cross multiply

Mass of gasoline = 0.7 × 15

Mass of gasoline = 10.5 Kg

2. Density has various units some are listed below:

I. Kilogram per litre (Kg/L)

II. Kilogram per cubic metre (Kg/m³)

III. Milligram per millilitre (mg/mL)

IV. Gram per millilitre (g/mL)

V. Gram per cubic centimetre (g/cm³)

Considering the options given in the question above, it is evident that second per gram (s/g) is not a unit of density because density is mass per unit volume.

3 0
2 years ago
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