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Licemer1 [7]
3 years ago
9

A 5.0 kg book is lying on a 0.25 meter high table.

Physics
1 answer:
Wittaler [7]3 years ago
3 0

Answer:

Below in the picture:-

I hope it helps.

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Example 9.1
docker41 [41]

v1f = -0.16 ms

Explanation:

Use the conservation law of linear momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where

v1i = v2i = 0

m1 = 160 kg

m2 = 0.50 kg

v2f = 50m/s

v1f = ?

So we have

0 = (160 kg)v1f + (0.5 kg)(50 m/s)

v1f = -(25 kg-m/s)/(160 kg)

= -0.16 m/s

Note: the negative sign means that its direction is opposite that of the arrow.

6 0
3 years ago
The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz. What is the period of the crystal's motion?
Elan Coil [88]

Answer:

Time period, T=3.05\times 10^{-5}\ s

Explanation:

Given that,

The quartz crystal used in an electric watch vibrates with a frequency of 32,768 Hz, f = 32768 Hz

We need to find the period of the crystal's motion. The relationship between the frequency and the time period is given by :

T=\dfrac{1}{f}

T is the time period of the crystal's motion.

Time period is given by :

T=\dfrac{1}{32768}

T=3.05\times 10^{-5}\ s

So, the time period of the crystal's motion is 3.05\times 10^{-5}\ s. Hence, this is the required solution.

8 0
3 years ago
A worker drives a 0.554 kg spike into a rail tie with a 2.30 kg sledgehammer. The hammer hits the spike with a speed of 62.7 m/s
Goryan [66]

Answer:

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

Explanation:

Given

Weight of sledge hammer = 2.30 kilogram

Speed of sledge hammer = 62.7 meter per second

Kinetic energy is equal to half the product of mass and velocity square

K E = \frac{1}{2} mv^2

Substituting the value of mass and velocity, we get -

KE = 0.5 * 2.30 * 62.7^2\\KE = 4520.9835

It is given that one fourth of the energy is converted into internal energy

One fourth of kinetic energy is equal to

\frac{1}{4} * 4520.9835\\= 1130.246

Increase in total energy will be equal to the increase in the internal energy i.e 1130.246 Joules

8 0
3 years ago
Read 2 more answers
What is the wavelength of an earthquake wave if it has a speed of 6 km/s and a frequency of 13 Hz?
PtichkaEL [24]
Velocity can be calculated using the following rule:
velocity = lambda * frequency where:
velocity is given = 6 km/sec
lambda is the wavelength that we want to calculate
frequency is given = 13 Hz

Substitute with the givens in the above equation to get the wavelength (lambda) as follows:
6 = 13*lambda
wavelength = 6/13 = 0.461538 Km = 461.538 meters
5 0
3 years ago
A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

      n = 1

            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

            f_2 =2\times \dfrac{50}{2\times 2}

                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

8 0
3 years ago
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