Answer:
The scientist will be looking for the velocity of the wave in air which is equivalent to 10^7m/s
Explanation:
If an object in space is giving off a frequency of 10^13Hz and wavelength of 10^-6m then the scientist will be looking for the velocity of the object in air.
The relationship between the frequency (f) of a wave, the wavelength (¶) and the velocity of the wave in air(v) is expressed as;
v = f¶
Given f = 10^13Hz and ¶ = 10^-6m,
v = 10¹³ × 10^-6
v = 10^7 m/s
The value of the velocity of the object in space that the scientist will be looking for is 10^7m/s
Answer:
IDK
Explanation:
IM sorry ppl i need to answer 5 questions for a task:) so dont mind me lol
Answer: (A) 3.0=A
Explanation: In order to explain this problem we have to use the OHM law, given by: V=R*I
Besides, we have to consider the resitance equivalent for a parallel connection. This is given by:
1/Re=1/R1+1/R2
If we connect the same resistance, the equivalent resistance is R/2.
Initlally the current is 1.5 A when one resistance is connected to the batttery. When a second resistance with the same value is connected in parallel to the battery, we have V=Re*Ifinal= (R/2)*Ifinal
also we know that V=R*Iinitial so Iinitial=V/R
then Ifinal= 2*V/R=2*Iinitial
Answer:
100 V
Explanation:
Hi there!
Ohm's law states that 
where V is the voltage, I is the current and R is the resistance.
Plug the given information into Ohm's law (R=50, I=A)
Therefore, the voltage across this current is 100 V.
I hope this helps!
