Answer:
Period of one vibration = 0.00215 second (Approx.)
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
Explanation:
Given:
Frequency of wave = 466 Hz
Find:
Period of one vibration
Wavelength {Is speed of sound is 343 m/s]
Computation:
Period of one vibration = 1/F
Period of one vibration = 1 / 466
Period of one vibration = 0.00215 second (Approx.)
Wavelength = Velocity / Frequency
Wavelength {Is speed of sound is 343 m/s] = 343 / 466
Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)
Answer:
Δ h = 52.78 m
Explanation:
given,
Atmospheric pressure at the top of building = 97.6 kPa
Atmospheric pressure at the bottom of building = 98.2 kPa
Density of air = 1.16 kg/m³
acceleration due to gravity, g = 9.8 m/s²
height of the building = ?
We know,
Δ P = ρ g Δ h
(98.2-97.6) x 10³ = 1.16 x 9.8 x Δ h
11.368 Δ h = 600
Δ h = 52.78 m
Hence, the height of the building is equal to 52.78 m.
