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pantera1 [17]
3 years ago
5

2.What is the basis for most ecosystem

Physics
1 answer:
lubasha [3.4K]3 years ago
4 0
Hey! the answer would be the sun. sunlight is needed to produce natural sugars and glucose. hope that helps ;)
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Linda is a forensic scientist arriving at the crime scene. What must she do before she can examine the crime scene?
Bezzdna [24]

Answer:

In the more scientific viewpoint, the most important thing that she must do is caring for her hygiene and put some plastic gloves in her hands.

This is because there are lots of particles that can be retained in the hands (dust, skin, etc), and when examining the scene, she may drop some of these particles, "contaminating" the scene in this way with information that only will affect the investigation.

So the most important thing is being prepared to not affect anything in the crime scene

7 0
3 years ago
Read 2 more answers
What happens to gravitational potential energy as a roller coaster moves down a hill?
Kaylis [27]
It is converted to kinetic energy.
5 0
3 years ago
Which statement is true if the refractive index of medium A is greater than that of medium B?
allsm [11]

Answer:

I think it is C

Explanation:

7 0
3 years ago
Two identical loudspeakers 2.00 m apart are emitting sound waves into a room where the speed of sound is 340 m/s. Abby is standi
Ganezh [65]

Answer:

242.85 Hz

Explanation:

For maximum intensity of sound, the path difference,ΔL = (n + 1/2)λ/2 where n = 0,1,2...

Since Abby is standing perpendicular to one speaker, the path length for the sound from the other speaker to him is L₁ = √(2.00² + 5.50²) = √(4.00 + 30.25) = √34.25 = 5.85 m.

The path difference to him is thus ΔL = 5.85 m - 5.50 m = 0.35 m.

Since ΔL = (n + 1/2)λ/2 and for lowest frequency n = 0,

ΔL = (n + 1/2)λ/2 = (0 + 1/2)λ/2 = λ/4

ΔL = λ = v/f and f = v/4ΔL where f = frequency of wave and v = velocity of sound wave = 340 m/s.

f = 340/(4 × 0.35) = 242.85 Hz

5 0
3 years ago
A quantity of a gas is an absolute pressure of 400 K PA in the absolute temperature of 110° Kelvin when the temperature of the g
aliina [53]

Given:

P1 = 400 kPa
T1 = 110 K

T2 = 235K

Required:

P2

Solution:

Apply Gay-Lussac’s law where P/T = constant

P1/T1 = P2/T2

P2 = T2P1/T1

P2 = (235K)(400kPa) / (110K)

P2 = 855 kPa

4 0
3 years ago
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