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3 years ago

True or False: When using a permutation, order matters. False True

Mathematics

1 answer:

GrogVix [38]3 years ago

3 0

Permutations means a set or number of things can be arranged or ordered.
Answer: True

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The numbers of blocked intrusion attempts on each day during the first two weeks of

Marrrta [24]

<u>(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)</u>

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3 years ago

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The baker pays $0.80 per pound for sugar and $1.25 per pound for butter. Which of the following equations shows t, how much the

Lynna [10]

Answer:

(6 x $1.25) + (20 x $0.80)

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3 years ago

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One number is five less than a second number. Five times the first is 15 more than 6 times the second. Find the numbers

Shalnov [3]

Answer:

x = -45, y = -40

Step-by-step explanation:

Based on the first clue, we find out that

x + 5 = y

5x = 6y + 15

We can re-write the first equation to x = y - 5.

Therefore, the second equation can also be written as 5(y - 5) = 6y + 15

This can be simplified to 5y - 25 = 6y + 15

We can subtract 6y from each side, and add 25 to each side;

5y - 6y = 15 + 25

Therefore, -y = 40

Therefore y = -40.

Now let's plug this back into the original equation, to get : x + 5 = -40

x=-45

4 0

3 years ago

5 POINTS !! ANSWER FASTTT

MariettaO [177]

N= 2

Substitute 2 in for n in expression

=(5 + n) ÷ (n - 1)
=(5 + 2) ÷ (2 - 1)
=7 ÷ 1
=7

If n= 2, the expression equals 7.

Hope this helps! :)

3 0

3 years ago

In order to test for the significance of a regression model involving 3 independent variables and 47 observations, the numerator

matrenka [14]

Answer:

The correct option is C

Step-by-step explanation:

From the question we are told that

The number of independent variables is $n = 3$

The number of observation is $z = 47$

Since n is are independent variables then their degree of freedom is 3

The denominator(i.e z) degrees of freedom is evaluated as

$Df(z) = z - (n +1)$

$Df(z) = 47 - (3 +1)$

$Df(z) = 43$

So for the numerator (n) the degree of freedom is Df(n) = 3

So for the denominator(i.e z) the degree of freedom is Df(z) = 43

4 0

4 years ago