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Murrr4er [49]
1 year ago
12

Calculate the volume of water which was liberated during the decomposition of hydrogen peroxide.

Chemistry
1 answer:
nikitadnepr [17]1 year ago
4 0

The answer is :

The normal equation for the decomposition of hydrogen peroxide indicates that 2 vol. peroxide vapor should give rise to 2 vol. water vapor and 1 vol. oxygen.

What is hydrogen peroxide ?

  • Hydrogen peroxide is water (H2O) with an extra oxygen molecule (H2O2).
  • The extra oxygen molecule oxidizes, which is how peroxide gets its power says Dr. Beers.
  • This oxidation kills germs and bleaches color from porous surfaces like fabrics.
  • Hydrogen peroxide is found in biological systems including the human body.
  • Enzymes that use or decompose hydrogen peroxide are classified as peroxidases.

To learn more about Hydrogen peroxide visit: brainly.com/question/18709693?

#SPJ4

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Read 2 more answers
what was the initial pressure of 14.8 mL of gas at 75.5 C , when it occupied a volume of 16.5 mL at 70.2 C and 101.3 kPa?
OLEGan [10]

Answer:

1038.96 kPa

Explanation:

We’ll use the ideal gas law; P1V1/T1 = P2V2/T2

P1*14.8/75.5 = 101.3*16.5/70.2

P1 = (101.3 * 16.5 * 75.5) / (70.2 *14.8)

P1 = 1038.96

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