Hmm
what you do is try to eliminate 1 variable in 2 equaions first
we can elminate x's in first and 2nd equation
add first and 2nd equation
x+3y-2z=10
<u>-x-2y+z=-7 +</u>
0x+y-z=3
y-z=3
multiply 2nd equation by 3 and add to last one
-3x-6y+3z=-21
<u>3x+9y-5z=28 +</u>
0x+3y-2z=7
3y-2z=7
we now have
y-z=3
3y-2z=7
multiply first equation by -2 and add to 2nd
-2y+2z=-6
<u>3y-2z=7 +</u>
y+0z=1
y=1
now we can sub back
y-z=3
1-z=3
minus 1
-z=2
times -1
z=-2
sub baack into any equation
x+3(1)-2(-2)=10
x+3+4=10
x+7=10
minus 7
x=3
x=3
y=1
z=-2
(3,1,-2)
12 is not a perfect square, but 4, a factor of 12, is a perfect square. Thus, separate the problem
sqrt(12) into factors as follows:
sqrt(12) = sqrt(4)*sqrt(2) = 2*sqrt(2) (answer)
1/4 =2/8+3/8 =5/8
1-5/8=3/8
Answer:
-20n/3n
Step-by-step explanation:
-4 1
--- / ---
9n 15n
Keep, change, flip
- Keep the -4/9n
- Change the division sign to a multiplication sign
- Flip the 1/15n to 15n/1
-4 15n
--- * ---
9n 1
Cross simplify.
9n divided by 3 is 3n.
15n divided by 3 is 5n.
-4 5n
--- * ---
3n 1
-4 times 5n equals -20n
3n times 1 equals 3n
-20n
---
3n
Remove parentheses
2/5 • d-10 - 2/3 • d+6
calculate
2/5d-4 - 2/3d-4
the answer
-4/15d-8
