Answer:
4
Step-by-step explanation:
2 and 9 thousandths. That is in word form
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:


Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:


Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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Answer:
Last option

Step-by-step explanation:

If we extract a sample of size n from a normal population and we want to estimate the population mean then the confidence interval for the mean will be:

Where
Where
is an estimator for the mean μ.
n is the sample size and s is its standard deviation.
is the level of significance
= 1-Confidence Level

Then 
Then the 99% confidence interval for the population mean is

Answer:
-22/3
Step-by-step explanation:
to convert a mixed number to an improper fraction:
whole number × denominator + numerator
keep the denominator
-8 × 3 + 2
-24 + 2
-22
keep denominator
-22/3