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2 years ago

Answer plz asap.......

Mathematics

1 answer:

dangina [55]2 years ago

5 0

Im not sure but I’ll go with c :)

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Where is the hundred thousand place

ozzi

The 6th to the left

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2 years ago

Cleatus pulled into the neighborhood gas station to fill his car with gas. The 91-octane gas is selling for $2.08 per gallon. He

Dafna1 [17]

Answer: $47.60

Step-by-step explanation: First, we will multiply $2.08 by 20 because we want to know how much it will cost for 20 gallons of gas.

$2.08 x 20 = $41.60

Now, just add the $6.00 car wash to the total amount of gas which is $41.60.

$41.60 + $6.00 = $47.60

So, the total amount of his purchase was $47.60

7 0

2 years ago

Math Help Please....

stich3 [128]

Triangle ABE is similar to triangle CED (AAA)
10/8 = (2x+6) / (x+6)
x=2
therefore AE = 2(2) + 6
= 10 units

5 0

2 years ago

(x+6)x-3)help me pleases

Oksanka [162]

X^2 +3x - 18 is the answer

8 0

3 years ago

(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this

Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

$\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta$

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

$\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta$

Simplify. The denominator uses the difference of two squares pattern:

$\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta$

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

$\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta$

Split into two separate fractions:

$\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta$

Rewrite the two fractions:

$\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta$

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

$\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=} \sec^2\theta - \sec\theta\tan\theta$

Hence verified.

8 0

2 years ago

Answer plz asap.......​

Answer plz asap.......