Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm
now, write the question as a system of equations
3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300
now you have a system of equations
3x+2y =200
4x+4y =300
solve for x and y
The answer may be c but if not i am super sorry!!
Answer:
C. y = 2 (x + 3)³ − 4
Step-by-step explanation:
y = x³
Stretch vertically by 2.
y = 2x³
Shift horizontally 3 units to the left.
y = 2 (x + 3)³
Shift vertically 4 units down.
y = 2 (x + 3)³ − 4
The answer you're looking for is, x = 3,-5
<u>We are given the equation:</u>
(a + b)! = a! + b!
<u>Testing the given equation</u>
In order to test it, we will let: a = 2 and b = 3
So, we can rewrite the equation as:
(2+3)! = 2! + 3!
5! = 2! + 3!
<em>We know that (5! = 120) , (2! = 2) and (3! = 6):</em>
120 = 2 + 6
We can see that LHS ≠ RHS,
So, we can say that the given equation is incorrect
