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3 years ago

7

Please help ASAP lol

1 answer:

MAXImum [283]3 years ago

4 0

B and C are the correct answers

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Solve.<br> X = -7<br> 4x - 4y = 12<br> (x,y)

Fynjy0 [20]

Answer:

(-7, -10)

$x=-7\\y=-10$

Step-by-step explanation:

$4x-4y=12$

Substitute x for -7.

$4(-7)-4y=12$

Multiply 4 by -7.

$-28-4y=12$

Add 28 on both sides.

$-4y=40$

Divide -4 on both sides.

$y=-10$

4 0

3 years ago

Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl

amm1812

Answer:

1. $P(s_1|I)=\frac{1}{11}$

2. $P(s_2|I)=\frac{8}{11}$

3. $P(s_3|I)=\frac{2}{11}$

Step-by-step explanation:

Given information:

$P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3$

$P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1$

(1)

We need to find the value of P(s₁|I).

$P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}$

$P(s_1|I)=\frac{0.015}{0.165}$

$P(s_1|I)=\frac{1}{11}$

Therefore the value of P(s₁|I) is $\frac{1}{11}$ .

(2)

We need to find the value of P(s₂|I).

$P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}$

$P(s_2|I)=\frac{0.12}{0.165}$

$P(s_2|I)=\frac{8}{11}$

Therefore the value of P(s₂|I) is $\frac{8}{11}$ .

(3)

We need to find the value of P(s₃|I).

$P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}$

$P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}$

$P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}$

$P(s_3|I)=\frac{0.03}{0.165}$

$P(s_3|I)=\frac{2}{11}$

Therefore the value of P(s₃|I) is $\frac{2}{11}$ .

4 0

3 years ago

(Look at picture.............)

Tpy6a [65]

Answer:

3460

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

0.3 x 103<br>0 3 x 1025<br>Write the following as an ordinary number. [<br>(1 Point<br>3x10

Ne4ueva [31]

0.3 x 103 = 30.9
0.3 x 1025 = 307.5

3 x 10^5 = 300,000

3 0

3 years ago

Rabbit populations can double every 30 days. If there are 26 rabbits on a farm, how many rabbits will be on the farm after 240 d

Cerrena [4.2K]

Answer:

7680 rabbits

Step-by-step explanation:

Let y represent the number of rabbits after x days and let x represent the number of days. This is an exponential growth equation in the form:

$y=ab^x$

Since there is an initial value of 26 rabbits on the farm and the rabbits double every 30 days, hence the equation becomes:

$y=26(2^{(\frac{x}{30} )})\\\\for\ 240\ days, i.e\ x=240:\\\\y=26(2^\frac{240}{30} )\\\\y=7680\ rabbits$

8 0

3 years ago