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Marianna [84]
3 years ago
9

Expand and reduce (2+√3)^2

Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0

Answer:

7 + 4\sqrt{3}

Step-by-step explanation:

note that \sqrt{a} × \sqrt{a} = a

Given

(2 + \sqrt{3} )² = (2 + \sqrt{3} )(2 + \sqrt{3} )

Each term in the second factor is multiplied by each term in the first factor, that is

2(2 + \sqrt{3} ) + \sqrt{3}(2 + \sqrt{3} ) ← distribute both parenthesis

= 4 + 2\sqrt{3} + 2\sqrt{3} + 3 ← collect like terms

= 7 + 4\sqrt{3}

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Write the integral that gives the length of the curve y = f (x) = ∫0 to 4.5x sin t dt on the interval ​[0,π​].
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Answer:

Arc length =\int_0^{\pi} \sqrt{1+[(4.5sin(4.5x))]^2}\ dx

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Step-by-step explanation:

The arc length of the curve is given by \int_a^b \sqrt{1+[f'(x)]^2}\ dx

Here, f(x)=\int_0^{4.5x}sin(t) \ dt interval [0, \pi]

Now, f'(x)=\frac{\mathrm{d} }{\mathrm{d} x} \int_0^{4.5x}sin(t) \ dt

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Step-by-step explanation:

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