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2 years ago

Write the inequality shown by the shaded region in the graph with the boundary line y=x-2

Mathematics

2 answers:

evablogger [386]2 years ago

8 0

Answer:

y ≥ x - 2

Step-by-step explanation:

I'm pretty sure this will be the answer, a thanks a rating of a 5 star would be helpful :)

vladimir2022 [97]2 years ago

8 0

Answer:

The answer is y ≥ x - 2

Step-by-step explanation:

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Please help me quickly!

Degger [83]

Answer:

√50

Step-by-step explanation:

Use Pythagorean Theorem: a^2+b^2=c^2

5^2+5^2=c^2

25+25=c^2

50=c^2

c=√50

3 0

2 years ago

Read 2 more answers

Joe biked the following distances this past week to train for a triathlon. Joe biked 37 miles, 88 miles, 44 miles, 54 miles, 62

Artyom0805 [142]

Answer:

The median is 50.

Step-by-step explanation:

First you put all the numbers in order. (37, 44, 46, 54, 62, 88) then you look for the middle number. Since there is two middle numbers, you add them together then divide it by 2.

So 46+54= 100

100/2= 50

8 0

2 years ago

Find a quadratic function in standard form for each set of points

otez555 [7]

For 1 the equation of the parabola is y = x^2 - 8x + 3
For 2 the equation of the parabola is y = -2x^2 - 3x + 1
For 3 the equation of the parabola is y = -x^2 + 5x - 4

5 0

2 years ago

Give the intervals where f(x) is concave up. (enter your answer using interval notation. if an answer does not exist, enter dn

Kipish [7]

Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.

6 0

3 years ago

Write the Slope-Intercept and Point-Slope forms of the line passing through the point (-3, 2) and having a slope of -4/5

weeeeeb [17]

Answer:

slope-intercept: $y=\frac{-4}{5} x-\frac{2}{5}$

point-slope: $y-2=\frac{-4}{5} (x+3)$

Step-by-step explanation:

The slope-intercept form of a line is written as y = mx + b, where m is the slope and b is the y-intercept.

The point-slope form of a line is written as y - y1 = m(x - x1), where (x1, y1) is a given point and m is the slope.

Here, we see that the slope is -4/5, which means that m = -4/5. Since we're given a point (-3, 2), let's go ahead and just write the point-slope form already. (x1, y1) = (-3, 2) so x1 = -3 and y1 = 2. Then:

y - y1 = m(x - x1)

y - 2 = (-4/5) * (x + 3)

$y-2=\frac{-4}{5} (x+3)$

Now, we want to find the slope-intercept form, so we need to figure out the y-intercept. Well, first, let's plug in what we know:

y = mx + b

y = (-4/5)x + b

Any point on this line will satisfy the above equation. Since (-3, 2) is on this line, if we plug -3 in for x and 2 in for y, the equation should hold true, so we can solve for b:

y = (-4/5)x + b

2 = (-4/5) * (-3) + b

2 = 12/5 + b

b = -2/5

So, the y-intercept is -2/5. Then the slope-intercept form is:

$y=\frac{-4}{5} x-\frac{2}{5}$

Thus, our two equations are:

slope-intercept: $y=\frac{-4}{5} x-\frac{2}{5}$

point-slope: $y-2=\frac{-4}{5} (x+3)$

8 0

2 years ago