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3 years ago

Write the inequality shown by the shaded region in the graph with the boundary line y=x-2

Mathematics

2 answers:

evablogger [386]3 years ago

8 0

Answer:

y ≥ x - 2

Step-by-step explanation:

I'm pretty sure this will be the answer, a thanks a rating of a 5 star would be helpful :)

vladimir2022 [97]3 years ago

8 0

Answer:

The answer is y ≥ x - 2

Step-by-step explanation:

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Morgarella [4.7K]

27 is a perfect cube

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i need help asap!! Which of the following statements is false? Most absolute value equations will yield two different solutions.

Bezzdna [24]

the false statement is: the absolute value of a number can be negative.

the absolute value of a number is never negative

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3 years ago

What is the slope for (2, -1) and (3,1)

ale4655 [162]

Answer: 2

Step-by-step explanation:

m = y2 - y1 / x2- x1

where slope is m,

so in this case it would be

m= 1-(-1) / 3-2

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Note that you can do it either way

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3 years ago

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the total attendance at a concert in a theater hall was 1500, of this total 400 were children,850 were women , and the remaining

AleksandrR [38]

Answer:

Below!

Step-by step explanation:

We know that:

400 + 850 + m = 1500

Solution of Question A:

Percent of children: Total children/Total attendance

=> 400/1500
=> 4/15
=> 0.27 (Rounded to nearest hundredth)
=> 0.27 x 100
=> 27%

Hence, the percent of children is about 27%.

Solution of Question B:

Percent of women: Total women/Total attendance

=> 850/1500
=> 85/150
=> 17/30
=> 17/30 x 100
=> 17/3 x 10
=> 170/3
=> 56.67%

Hence, the percent of women is 56.67%.

Solution of Question C:

400 + 850 + m = 1500
=> 1250 + m = 1500
=> m = 1500 - 1250
=> m = 250

Percent of men: Total men/Total attendance

=> 250/1500
=> 1/6
=> 0.17 (Rounded to nearest hundredth)
=> 0.17 x 100
=> 17%

Hence, the percent of men is about 17%

Hoped this helped.

$BrainiacUser1357$

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2 years ago

find the sum of a 9-term geometric sequence when the first term is 4 and the last term is 1,024 and select the correct answer be

olasank [31]

Hello,

$u_{1} =4\\
 u_{2} =4*q\\
 u_{3} =4*q^2\\
...\\

 u_{9} =4*q^8\\\\
==\textgreater\ 4*q^8=1024\\
==\textgreater\ q^8=256\\
==\textgreater\ q=2\mbox{( and there is a problem in the question) } \ or \ q=-2\\
if\ q=2 \ then\ \sum_{i=0}^{8}\ 4*(2)^i= 4*\dfrac{1-2^9}{1-2} =2044\\

if \ q=-2 \ then\ \sum_{i=0}^{8}\ 4*(-2)^i= 4*\dfrac{1-(-2)^9}{1+2} =684\\



$

Answer B (but see the problem)

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