Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer: It traveled 36,000 miles per hour.
Step-by-step explanation: 1/10 of a second x 36000 = 1 hour.
Answer:
$
Step-by-step explanation:
Let's assume
represents the number of pounds of fruit.
We need to multiply the number of pounds of fruit by the cost per pound.
This is $
, or in a simpler form, $
.
Xy = 54
x + y = 7
















x + y = 7
3.5 + 6.45i + y = 7
- (3.5 + 6.45i) - (3.5 + 6.45i)
y = 3.5 - 6.45i
(x, y) = (3.5 + 6.45i, (3.5 - 6.45i)
or
x + y = 7
3.5 - 6.45i + y = 7
- (3.5 - 6.45i) - (3.5 - 6.45i)
y = 3.5 + 6.45i
(x, y) = (3.5 - 6.45i, 3.5 + 6.45i)
The two numbers that add up to 7 and can multiply to 54 is 3.5 ± 6.45i.