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jarptica [38.1K]
3 years ago
13

Can someone solve this?

Mathematics
1 answer:
RoseWind [281]3 years ago
3 0
I can the company sold 3,00 units in 2008, and 5,00 in 2012
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Jackson bought 3 pounds of candies for $9.75. c What was the price of these candies in cents per ounce?
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Jackson bought 3*16 = 48 ounces for 975 cents. The unit price in cents per ounce is ...
   975 cents/(48 oz) = 20.3125 cents/oz
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A dog is given a dosage of 100 mg of antibiotics. The amount of antibiotics in the dog's bloodstream will decrease by 40% each h
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After each hour 60% ( or 0.60) of the drug will be present.

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Jason begins at the start of a path Andy rides his bike 11 1/2 miles on the path. The path is 12 1/4 miles long. What is the dis
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3/4 of a mile until he reaches the end of the path.

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3 years ago
A man bought a lot for 1200 and sold it for 1500. his percent of gain based on his purchase was
jok3333 [9.3K]

Answer: The percent gain was 25%.

Step-by-step explanation:

Given, Cost price of lot = $1,200

Selling price of lot = $1,500

The percent gain = \dfrac{\text{selling price- cost price}}{\text{cost price}}\times100

⇒ Percent gain =\dfrac{1500-1200}{1200}\times100\%

\Rightarrow\text{ Percent gain}=\dfrac{300}{1200}\times100\%\\\\\Rightarrow\text{ Percent gain}=\dfrac{1}{4}\times100\%\\\\\Rightarrow\text{ Percent gain}=25\%

Hence, the percent gain was 25% based on his purchase.

5 0
4 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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