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Lunna [17]
3 years ago
5

A collection of five coins has a value of $1 and consists of dimes and

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

For this case we propose a system of equations. We have to:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of quaters

We know that:

One dime equals 10 cents, $0.10

A quater equals 0.25 cents, $0.25

According to the statement we have:

x + y = 5\\0.10x + 0.25y = 1

We multiply the first equation by -0.10:

-0.10x-0.10y = -0.5

We have the following equivalent system:

-0.10x-0.10y = -0.5\\0.10x + 0.25y = 1

We add the equations:

-0.10x + 0.10x-010y + 0.25y = -0.5 + 1\\0.15y = 0.5\\y = \frac {0.5}{0.15}\\y = 3.33

Approximately 3 quater coins

x = 5-y = 5-3 = 2

And two dimes

Answer:

3 quater

2 dimes

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