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Lunna [17]
3 years ago
5

A collection of five coins has a value of $1 and consists of dimes and

Mathematics
1 answer:
DENIUS [597]3 years ago
4 0

For this case we propose a system of equations. We have to:

x: Let the variable that represents the number of dimes

y: Let the variable that represents the number of quaters

We know that:

One dime equals 10 cents, $0.10

A quater equals 0.25 cents, $0.25

According to the statement we have:

x + y = 5\\0.10x + 0.25y = 1

We multiply the first equation by -0.10:

-0.10x-0.10y = -0.5

We have the following equivalent system:

-0.10x-0.10y = -0.5\\0.10x + 0.25y = 1

We add the equations:

-0.10x + 0.10x-010y + 0.25y = -0.5 + 1\\0.15y = 0.5\\y = \frac {0.5}{0.15}\\y = 3.33

Approximately 3 quater coins

x = 5-y = 5-3 = 2

And two dimes

Answer:

3 quater

2 dimes

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Answer:

1/2

Step-by-step explanation:

look at all the numbers then look at only the negatives which are 2 then count the positive ones which are 4 from those numbers you get 2/4 simplify it, and you get 1/2.

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3 years ago
The sum of two numbers is 64 and the difference is 6. What are the numbers?
Ne4ueva [31]

Answer:

29 and 35

Step-by-step explanation:

x+y=64

x-y=6

Solve by substitution.

x=6+y

6+y+y=64

6+2y=64

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Then plug in 29 for y.

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A⋅a/\2⋅a/\3=?? I need help ASAP
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a^6

Step-by-step explanation:

a^1 * a^2 * a^3 = 1+2+3(add all power when same variable)

a^6

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Evaluate the expression, below, when a = 2 and b = 5. <br><br> (3 + a)² • (4 – b) + √36
stellarik [79]

Answer:

-19

Step-by-step explanation:

1) substitute a with 2 and b with 5

(3 + 2)^2 * (4-5) + √36

2) solve the brackets and the square root

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3) solve the power

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4) solve the multiplication

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