PLEASE HELP MEEEEEEEEEEEEEEEEEEEEEEEEEE!!! giving all the points I have

Mathematics

1 answer:

exis [7]3 years ago

3 0

Answer:

Plug in and determine solution

Step-by-step explanation:#9-11 plug in the degrees C on the left side of the table into the equation and that should give you the degrees F, something like with #9; F = 9/5 (0) + 32.

#12-13, they have a relationship because Celsius can be converted to Farenheit and vise versa

You might be interested in

The table shows the monthly salaries for employees at a company.

Nimfa-mama [501]

Answer:

Step-by-step explanation:

6 0

2 years ago

PLEASE HELP ! (4/4) - 50 POINTS -

slega [8]

Answer:

The correct answer, again, is A; Z = -0.6

7 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$