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3 years ago

Is the anyone one here that’s really good in math?

Mathematics

1 answer:

nalin [4]3 years ago

6 0

Yep..Tell me what do you wanna solve!?

You might be interested in

Select all the expressions that are equivalent to −5/6 / -1/3

Sindrei [870]

Step-by-step explanation:

We need to find an expression for $\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}$ .

We can solve it as follows.

We know that,

$\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}$

So,

$\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}=\dfrac{-5}{6}\times -3\\\\=\dfrac{5}{2}$

$=2\dfrac{1}{2}$

Hence, this is the required solution.

3 0

3 years ago

Tony is using these numbers to make a new number: 12, 1, 4, 7.

natulia [17]

Answer:

420

Step-by-step explanation:

(12 x 7) x (1+4)

84 x 5

=420

7 0

3 years ago

Cassie is thinking of two numbers. Adding 4 times the first number and 6 times the second number gives a total of 28. Also, addi

aleksandrvk [35]

If you try 6x4, you get 24. When you add 4, it = 28. The same thing with 6x4=24+5=29

3 0

3 years ago

In how many ways can 5 different novels, 4 different mathematics books, and 1 biology book be arranged on a bookshelf if: (a) Th

Zinaida [17]

Answer:

(a) 3628800 ways

(b) 17280 ways

Step-by-step explanation:

Given

$Novels = 5$

$Maths = 4$

$Biology = 1$

$Total = 10$

Solving (a): Arrangement with no restriction.

We simply count each book with no restriction. i.e. 10 books

So, the number of arrangement is:

$Arrangement =10!$

$Arrangement =10*9*8*7*6*5*4*3*2*1$

$Arrangement =3628800$

Solving (b): Maths book together and Novels together

First, arrange the 4 maths books as:

$Maths = 4!$

Next, arrange the 5 novels as:

$Novels = 5!$

Lastly, take the 4 maths book as [1], the 5 novels as [1] and the remaining [1] biology book.

So, we have: 3 books

Arrange 3 books, we have:

$Books = 3!$

Total arrangement is:

$Total = 4! * 5! * 3!$

$Total = 4*3*2*1 * 5*4*3*2*1 * 3*2*1$

$Total = 17280$

Solving (c): Maths book together

First, arrange the 4 maths books as:

$Maths = 4!$

Next, take the 4 maths book as [1], then the remaining 6 books (i.e. 5 novels and 1 biology)

So, we have: 7 books

Arrange 7 books, we have:

$Books = 7!$

Total arrangement is:

$Total = 4! * 7!$

$Total = 4*3*2*1 * 7*6*5*4*3*2*1$

$Total = 120960$

7 0

3 years ago

-8 - something = 3<br>I need help

nydimaria [60]

Answer:

-8 - -11 = 3

Step-by-step explanation:

$-8-x=3\\\\-8-x-3=3-3\\\\-11-x=0\\\\-11-x+x=0+x\\\\-11=x$

Therefore, the missing number is -11

4 0

2 years ago