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Minchanka [31]
3 years ago
5

A rope tied from a tent pole to a take in the ground forms 55 degrees angle with the ground. The pole is 3 feet from the stake,

what is the length of the rope to the nearest tenth of a foot
Mathematics
1 answer:
grin007 [14]3 years ago
8 0

Given:

A rope tied from a tent pole to a stake in the ground forms 55 degrees angle with the ground.

The pole is 3 feet from the stake.

To find:

The length of the rope to the nearest tenth of a foot.

Solution:

First draw a diagram according to the given information as shown below.

We know that, in a right angled triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

In triangle ABC,

\cos 55^\circ=\dfrac{BC}{AC}

0.573576=\dfrac{3}{AC}

AC=\dfrac{3}{0.573576}

AC=5.23034

AC\approx 5.2

Therefore, the length of the rope is 5.2 foot.

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A cylinder has diameter of 4ft and a height of 9ft. Explain whether halving the diameter has the same effect on the surface area
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Answer:

See Below

Step-by-step explanation:

The surface area of cylinder is given by the formula:

SA=2\pi r^2 + 2\pi r h

Where

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h is height ( h = 9)

Lets find original surface are:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (9)\\SA=8\pi +36\pi\\SA=44\pi

<u>Halving diameter:</u>

diameter would be 4/2 = 2, so radius would be 2/2 = 1

So, SA would be:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (1)^2 + 2\pi (1) (9)\\SA=2\pi +18\pi\\SA=20\pi

<u>Halving height:</u>

Height is 9, halving would make it 9/2 = 4.5

Now, calculating new SA:

SA=2\pi r^2 + 2\pi r h\\SA=2\pi (2)^2 + 2\pi (2) (4.5)\\SA=8\pi + 18\pi\\SA= 26\pi

Original SA is 44\pi,

Halving diameter makes it 20\pi

Halving height makes it 26\pi

So, halving diameter does not have same effect as halving height.

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Step-by-step explanation:

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