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Anna35 [415]
3 years ago
9

PLS HELP ME, 40 POINTS PLUS BRAINLIEST

Physics
1 answer:
bulgar [2K]3 years ago
5 0

Answer:

there is no question

Explanation:

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A sound wave has a frequency of 500 Hz and a wavelength of 1.8 m. What is the wave speed of the sound wave? Question 1 options:
antoniya [11.8K]

Answer:

The wave speed of the sound wave is 900 \frac{m}{s}.

Explanation:

Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

The propagation velocity is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement. Relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation: v = f * λ.

In this case:

  • f= 500 Hz
  • λ= 1.8 m

Replacing:

v= 500 Hz* 1.8 m

v= 900 \frac{m}{s}

<u><em>The wave speed of the sound wave is 900 </em></u>\frac{m}{s}<u><em>.</em></u>

7 0
3 years ago
n ultraviolet light beam having a wavelength of 130 nm is incident on a molybdenum surface with a work function of 4.2 eV. How f
pashok25 [27]

Answer:

The speed of the electron is 1.371 x 10⁶ m/s.

Explanation:

Given;

wavelength of the ultraviolet light beam, λ = 130 nm = 130 x 10⁻⁹ m

the work function of the molybdenum surface, W₀ = 4.2 eV = 6.728 x 10⁻¹⁹ J

The energy of the incident light is given by;

E = hf

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/s

f = c / λ

E = \frac{hc}{\lambda} \\\\E = \frac{6.626*10^{-34} *3*10^{8}}{130*10^{-9}} \\\\E = 15.291*10^{-19} \ J

Photo electric effect equation is given by;

E = W₀ + K.E

Where;

K.E is the kinetic energy of the emitted electron

K.E = E - W₀

K.E = 15.291 x 10⁻¹⁹ J - 6.728 x 10⁻¹⁹ J

K.E = 8.563 x 10⁻¹⁹ J

Kinetic energy of the emitted electron is given by;

K.E = ¹/₂mv²

where;

m is mass of the electron = 9.11 x 10⁻³¹ kg

v is the speed of the electron

v = \sqrt{\frac{2K.E}{m} } \\\\v =  \sqrt{\frac{2*8.563*10^{-19}}{9.11*10^{-31}}}\\\\v = 1.371 *10^{6} \ m/s

Therefore, the speed of the electron is 1.371 x 10⁶ m/s.

8 0
3 years ago
Is this right? I need help, thank you
erastovalidia [21]

Velocity is correct, the symbol for acceleration is a. That is all I know.

(As in f=m*a)

7 0
3 years ago
Aluminum has a specific heat of 0.902 J/g x oC. Two pieces of aluminum, with masses of 10 kg, cool from 400 oC to 100oC. One mas
Hunter-Best [27]

The heat energy lost is directly related to the shape of the object.

8 0
3 years ago
Read 2 more answers
How is electron affinity different from electronegativity
NeTakaya

Explanation:

Electronegativity is the ability of an atom to attract electrons, when it forms a chemical bond in a molecule. However, it is not strictly an atomic property, since it refers to an atom within a molecule. The equivalent property of electronegativity for an isolated atom is electronic affinity.

3 0
3 years ago
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