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topjm [15]
3 years ago
10

An object is placed 11.0 cm in front of a concave mirror whose focal length is 24.0 cm. The object is 2.60 cm tall. What is the

height of the image? (cm)
Physics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

Height of the image is 4.79 cm.

Explanation:

Object distance, u = -11 cm

Focal length of the mirror, f = -24 cm

Height of the object, h = 2.6 cm

We need to find the height of the image. Firstly, using the mirror's formula as :

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

v is the image distance

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{(-24)}-\dfrac{1}{(-11)}

v = 20.30 cm

The magnification of the image is given by :

m=\dfrac{-v}{u}=\dfrac{h'}{h}, h' is the height of the image

\dfrac{-v}{u}\times h={h'}

\dfrac{-20.30}{-11}\times 2.6={h'}

h' = 4.79 cm

So, the height of the image is 4.79 cm. Hence, this is the required solution.

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Nuetrik [128]

Answer:

Equator

Explanation:

The equator is the line of latitude that separates the earth into the northern and southern hemisphere.Its magnitude is 0 degrees latitude. The equator and other lines of latitude are parallel to each other. The lines of longitude which is 0 degrees is known as the Greenwich meridian. The longitudinal lines however are not parallel as they converge at the poles.

7 0
3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

#SPJ10

3 0
2 years ago
An object of mass 5 m is lifted to a height of 5 h above the floor. What is the potential energy the object gained in this proce
Gekata [30.6K]

Answer:

Potential energy, E = 25 mgh

Explanation:

Given that,

Mass of the object, m = 5 m

It is lifted to a height of, h = 5 h

It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :

E=m\times g\times h

E=5\ m\times g\times 5\ h

E = 25 mgh

So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.

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3 years ago
Which of the following statements are true?
yawa3891 [41]
A. False, because the SI unit for frequency is Hertz, 1 hertz equals 1 wave passing a fixed point in 1 second,

B. True, f and Nu (v)

C. To find the frequency of a wave, divide velocity of wave by wavelength

D. False, the period of a wave is measured in frequency (Hertz)
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What is the gravity of Earth?
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7 0
3 years ago
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