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topjm [15]
3 years ago
10

An object is placed 11.0 cm in front of a concave mirror whose focal length is 24.0 cm. The object is 2.60 cm tall. What is the

height of the image? (cm)
Physics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

Height of the image is 4.79 cm.

Explanation:

Object distance, u = -11 cm

Focal length of the mirror, f = -24 cm

Height of the object, h = 2.6 cm

We need to find the height of the image. Firstly, using the mirror's formula as :

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

v is the image distance

\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{(-24)}-\dfrac{1}{(-11)}

v = 20.30 cm

The magnification of the image is given by :

m=\dfrac{-v}{u}=\dfrac{h'}{h}, h' is the height of the image

\dfrac{-v}{u}\times h={h'}

\dfrac{-20.30}{-11}\times 2.6={h'}

h' = 4.79 cm

So, the height of the image is 4.79 cm. Hence, this is the required solution.

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