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3 years ago

A 18Ω resistance is cut into three equal parts and connected in parallel. Find the equivalent resistance of the combination.

Physics

1 answer:

Andrew [12]3 years ago

5 0

Answer:

2Ω

Explanation:

If a 18Ω resistance is cut into three equal parts each of the resistance will be 18Ω/3 = 6Ω

Equivalent ratio in parallel is expressed as:

1/R = 1/6 + 1/6 + 1/6

1/R = 3/6

Cross multiply

3R = 6

R = 6/3

R = 2Ω

Hence the required equivalent resistance is 2Ω

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What is the thinnest soap film (excluding the case of zero thickness) that appears black when illuminated with light with a wave

Firlakuza [10]

Answer:

thinnest soap film is 206.76 nm

Explanation:

Given data

wavelength = 550 nm

index of refraction n = 1.33

to find out

What is the thinnest soap film

solution

we have wavelength λ = 550 nm

that is λ = 550 × $10^{-9}$ m

and n = 1.3

we will find the thickness of soap film as given by formula that is

thickness = λ/2n

thickness = 550 × $10^{-9}$ / 2(1.33)

thickness = 206.76 × $10^{-9}$ m

thinnest soap film is 206.76 nm

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2 years ago

I need help on 2/3 please asap thx ♥️

ch4aika [34]

questions 2

F=m

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3 years ago

An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6

lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

$I = \frac{P_{avg}}{A}$

$I = \frac{P_{avg}}{4\pi r^2}$

$I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m$

$I = 6.529*10^{-6}W/m^2$

The amplitude of electric field at the receiver is

$I = \frac{E_{max}^2}{2\mu_0 c}$

$E_{max}= \sqrt{2I\mu_0 c}$

The amplitude of induced emf by this signal between the ends of the receiving antenna is

$\epsilon_{max} = E_{max} d$

$\epsilon_{max} = \sqrt{2I \mu_0 cd}$

Here,

I = Current

$\mu_0$ = Permeability at free space

c = Light speed

d = Distance

Replacing,

$\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}$

$\epsilon_{max} = 0.05434V$

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0

3 years ago

If jack was traveling north 120 miles and it took him 3 hours to get there. what is the velocity that jack was traveling? is thi

Dimas [21]

Answers:

40 mp/h; Vector

Reason:

120/3 is 40 miles per hour.

Velocity is a vector measurement.

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3 years ago

Which of the following describes the charge of an atom before any electrons are transferred?

Nadya [2.5K]

I am pretty sure that the following which describes the charge of an atom before any electrons are transferred is neutral charge. According to the fact that atom is always like that before ionization, this answer is definitely correct. Hope it helps!

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3 years ago