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Helga [31]
3 years ago
12

While discussing the effects of loose wheel bearings: Technician A says that vibration may occur while driving. Technician B say

s that the bearing may make noise. Who is correct? a. Technician A b. Neither A nor B c. Technician B d. Both A and B
Physics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

Option "D" is the correct answer i.e. Both Technicians A & B

Explanation:

Dear,

Loose wheel bearings can be caused on any machine.

The Following can be the reasons :

  • the machine or motor is installed improperly
  • the rotor(rotating part) of machine is not balanced
  • the cover get deteriorated with time
  • Bad manufacturer

So, when the bearings will be loose then the following can happen:

  1. It will produce vibration in machine which can be judged by a vibration pen eg. SKF vibration pen
  2. The vibration will also result in noise. You can check by
  3. The machine winding if it is motor will burn-out.
  4. Bush needs to be installed if the bearing runs loose.

Therefore,  "D" is right.

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A hammer taps on the end of a 5.0-mm-long metal bar at room temperature. A microphone at the other end of the bar picks up two p
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Answer:

810.37 m/s

Explanation:

s = Displacement = 5 m

v_a = Speed of sound in air = 343 m/s

Time taken to travel the distance

t'=\dfrac{s}{v_a}\\\Rightarrow t'=\dfrac{5}{343}\\\Rightarrow t'=0.01457\ s

Time for the sound in metal

t=0.01457-8.4\times 10^{-3}=0.00617\ s

Speed of sound is given by

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6 0
3 years ago
PART ONE
stepladder [879]

Answer:

1. A1, B2, C3

2. 47.1°

Explanation:

Sum of forces in the x direction:

∑Fₓ = ma

f − Fᵥᵥ = 0

f = Fᵥᵥ

Sum of forces in the y direction:

∑Fᵧ = ma

N − W = 0

N = W

Sum of moments about the base of the ladder:

∑τ = Iα

Fᵥᵥ h − W (b/2) = 0

Fᵥᵥ h = ½ W b

Fᵥᵥ (l sin θ) = ½ W (l cos θ)

l Fᵥᵥ sin θ = ½ l W cos θ

The correct set of equations is A1, B2, C3.

At the smallest angle θ, f = Nμ.  Substituting into the first equation, we get:

Nμ = Fᵥᵥ

Substituting the second equation into this equation, we get:

Wμ = Fᵥᵥ

Substituting this into the third equation, we get:

l (Wμ) sin θ = ½ l W cos θ

μ sin θ = ½ cos θ

tan θ = 1 / (2μ)

θ = atan(1 / (2μ))

θ = atan(1 / (2 × 0.464))

θ ≈ 47.1°

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Explanation:

This definition is provided by Oxford Languages

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