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noname [10]
3 years ago
14

A balloon with a charge of 4.0 x 10 -5C is held a distance of 0.10 m from a second balloon having the same charge. Calculate the

magnitude of the repulsive force.
Physics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

1438.4 N

Explanation:

Applying,

F = kqq'/r²................... Equation 1

Where F = Electrostatic force on the balloons, k = coulomb's constant, q = charge on the first balloon, q' = charge on the second balloon, r = distance between the two ballons.

From the question,

Given: q = q' = 4.0×10⁻⁵ C, r = 0.1 m

Constant: k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( 4.0×10⁻⁵×4.0×10⁻⁵×8.99×10⁹)/0.1²

F = 14.384/0.01

F = 1438.4 N

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Explanation:

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3 years ago
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A hiker, caught in a rainstorm might absorb 1 liter of water in her clothing. if it is windy so that this amount of water is eva
NeTakaya

Water evaporates at 100⁰C

So change in temperature = 100-20 = 80⁰C

Amount of water to be evaporated = 1 liter = 1L*1kg/liter = 1 kg

Specific heat of water is 1 calorie/gram ⁰C = 4.186 joule/gram =4186 J/kg

So heat required E = mcΔT = 1 * 4186 *80= 334880 J =334.88 kJ

So amount of heat require to evaporate water = 334.88 kJ

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3 years ago
Problem 10.64 the maximum energy a bone can absorb without breaking is surprisingly small. for a healthy human of mass 67 kg , e
kvasek [131]

Answer: h = 0.30 m

Explanation:

A person jumping from height h would possess potential energy = m g h

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m = 67 kg

g = 9.8 m/s²

⇒ m g h = 200 J

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8 0
3 years ago
If a particle undergoes shm with amplitude 0.21 m, what is the total distance it travels in one period?
Ymorist [56]
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
7 0
4 years ago
A sound wave has a speed of 340 m/s and a frequency of 1000 hz. The period of the sound is closest to?
harina [27]
<h2>Relationship Between Frequency and Period</h2>

The frequency and the period are inversely proportional.

f=\dfrac{1}{T} where T is the period

<h2>Solving the Question</h2>

We're given:

  • <em>v</em> = 340 m/s
  • <em>f</em> = 1000 Hz

Because the frequency and the period are reciprocals of each other, we can find the period of the sound by finding the reciprocal of the frequency:

T=\dfrac{1}{1000}

<h2>Answer</h2>

T=\dfrac{1}{1000}

6 0
2 years ago
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