A balloon with a charge of 4.0 x 10 -5C is held a distance of 0.10 m from a second balloon having the same charge. Calculate the
1 answer:
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Answer:
From the formula of force:
since AB and k are constants:
x is a constant of proportionality
• when force is 4N, separation distance is 1
therefore, equation becomes
when r is doubled, r becomes 2. find F:
Answer:
Explanation:
Energy of signal being radiated per second on all sides = 71 x 10³ J .
At a distance of 220 m it is spread over an area of 4 π x (220)² because it is spreading uniformly on all sides.
So energy crossing per unit area
=
= 11.67 x 10⁻² Wm⁻²s⁻¹.
This is the intensity of the signal.
At 2200 m this intensity will further reduce by 100 times
So there it becomes equal to
11.67 x 10⁻⁴ Wm⁻² s⁻¹.