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noname [10]
3 years ago
14

A balloon with a charge of 4.0 x 10 -5C is held a distance of 0.10 m from a second balloon having the same charge. Calculate the

magnitude of the repulsive force.
Physics
1 answer:
wolverine [178]3 years ago
3 0

Answer:

1438.4 N

Explanation:

Applying,

F = kqq'/r²................... Equation 1

Where F = Electrostatic force on the balloons, k = coulomb's constant, q = charge on the first balloon, q' = charge on the second balloon, r = distance between the two ballons.

From the question,

Given: q = q' = 4.0×10⁻⁵ C, r = 0.1 m

Constant: k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( 4.0×10⁻⁵×4.0×10⁻⁵×8.99×10⁹)/0.1²

F = 14.384/0.01

F = 1438.4 N

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Answer:

Because the object should shrink its volume to zero, which is impossible

Explanation:

Let's talk about gases for simplicity. Ideal gases are governed by the ideal gas equation:

pV=nRT

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n is the number of moles

R is the gas constant

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From the formula, we see that T and V are directly proportional: therefore, in order for a gas to have an absolute temperature of zero, it must also have a volume of zero, which is impossible.

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Answer:

32.1 N Please Give Brainliest

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2 years ago
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Answer:

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