Question

A balloon with a charge of 4.0 x 10 -5C is held a distance of 0.10 m from a second balloon having the same charge. Calculate the magnitude of the repulsive force.

Answer 1

Answer:

1438.4 N

Explanation:

Applying,

F = kqq'/r²................... Equation 1

Where F = Electrostatic force on the balloons, k = coulomb's constant, q = charge on the first balloon, q' = charge on the second balloon, r = distance between the two ballons.

From the question,

Given: q = q' = 4.0×10⁻⁵ C, r = 0.1 m

Constant: k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( 4.0×10⁻⁵×4.0×10⁻⁵×8.99×10⁹)/0.1²

F = 14.384/0.01

F = 1438.4 N