Force is mass into acceleration
and pressure is force applied per unit area.
Answer:
e. all three objects possess charges of the same sign.
Explanation:
We know that objects with same polarity will repel each other while objects with opposite polarity will attract each other. Here objects A and B repel each other which means they possess the charge of same polarity. Objects B and C also repel each other which means that they also possess the same polarity (sign).
This means that A and C will also repel each other. All the three objects possess the charge with same polarity.
Answer:
Weight on Jupiter will be equal to 2940 N
Explanation:
We have given given acceleration due to gravity on Jupiter is 3 times of acceleration due to gravity on earth
Acceleration due to gravity on earth
So acceleration due to gravity on Jupiter =
Mass is given m = 100 kg
We have to find the weight
Weight is equal to W = mg, here m is mass and a is acceleration
So weight
Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0 cm. Each plate has a surface charge density of 49.0 nC/m2. A proton is released from rest at the positive plate.
(a) Determine the magnitude of the electric field between the plates from the charge density.
b) Determine the potential difference between the plates.
Answer:
a
The Electric Field between the two plate is
b
The potential difference between the plate is V =
Explanation:
From the we are given that
The separation between the plate is
The surface charge density is
Generally Electric field between the plate is mathematically given as
Note that is the permitivity of free space and its value is
Now substituting values we have
Generally Potential difference between the plate is mathematically given as
Where E is the electric field which is
Substituting value we have
V =
Answer:
a) 5m/s2
b) 4 sec
c) 6 sec
d) 90 m
e) Answer in the file attached as it is a graph
Explanation:
This question can be solved using equations of motion. The two equations are:
2(a)(s) = v² – u²
v = u + (a)(t)
a = acceleration
s = distance
v = final velocity
u = initial velocity
t = time
a) Given final velocity = 50m/s and initial velocity = 30 m/s for 160m journey
Using 2(a)(s) = v² - u²
2(a)(160) = 50² – 30²
320 (a) = 2500 - 900
a = 1600/320
a = 5m/s²
b) The acceleration remains constant throughout so we can use it in this part as well.
Using v = u + (a)(t)
50 = 30 + (5)(t)
t = 4 sec
c) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using v = u + (a)(t)
30 = 0 + 5(t)
t = 6 sec
d) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using 2(a)(s) = v² - u²
2(5) (s) = 30² – 0²
10(s) = 900
s = 90 m
e) Graphs are attached as image