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Lera25 [3.4K]
3 years ago
15

During the execution of a play, a football player carries the ball for a distance of 33 m in the direction 58° north of east. To

determine the number of meters gained on the play, find the northward component of the ball's displacement.
Physics
1 answer:
podryga [215]3 years ago
8 0

Answer:28 m

Explanation:

Given

Direction is 58^{\circ} North of east i.e. 58 ^{\circ} with x axis

Also ball moved by 33 m

therefore its east component is 33cos58=17.48 m

Northward component =33sin58=27.98 m\approx 28 m

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Two speakers separated by a distance of 4.40 m emit sound. The speakers have opposite phase. A person listens from a location 3.
Hoochie [10]

Answer:

f = 147.21 Hz

Explanation:

In order to have a destructive interference, as the source emit in opposite phases, the path difference between the distance to the person, measured in a straight line from the speakers, must be equal to an integer number of wavelengths.

We need to know the distance from the listener to the other speaker, located 4.4 m from the one which is directly in front of him, which we can find using Pythagorean theorem, as follows:

l₂ = √(3)²+(4.4)² = 5.33 m

The difference in path will be, then:

d = l₂-l₁ = 5.33 m - 3.00 m = 2.33 m

For the lowest frequency that gives destructive interference, the wavelength will be highest possible, which happens when the distance is just one wavelength.

⇒ d = λ = 2.33 m

In any wave, there exists a fixed relationship between speed, frequency and wavelength, as follows:

v = λ*f Κ  ⇒ f = v/λ

Taking the speed of sound as 343 m/s, and solving for f, we get:

f= 343 m/s / 2.33 m = 147.21 Hz

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3 years ago
On a planet where g = 10.0 m/s2 and air resistance is negligible, a sled is at rest on a rough inclined hill rising at 30°. The
Cloud [144]

Answer:

Explanation:

a is the acceleration

μ is the coefficient of friction

Acceleration of the object is given by

a = g (\sin  \theta -\mu \cos \theta)\\\\=10( \sin 30 - 0.4 \cos 30)\\\\=10(0.5-0.3464)\\\\=1.54m/s^2

Velocity at the bottom

v^2=u^2+2as\\\\u=0\\\\v^2=2as\\\\=2*1.54*8\\\\=24.576\\\\v=4.96m/s

after travelling 4m , its velocity becomes 0

a=\frac{v^2-u^2}{2s}

a=\frac{0-u^2}{2s}

a=\frac{-(-4.96)^2}{2*4} \\\\=-3.075m/s^2

Coefficient of kinetic friction

μ = F/N

=\frac{ma}{mg} \\\\=\frac{3.075}{10} \\\\=0.31

Therefore, the Coefficient of kinetic friction is 0.31

8 0
2 years ago
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hichkok12 [17]

Answer:

\boxed{\sf Focal \ length = 10 \ cm}

Given:

Radius of curvature (R) of a spherical mirror = 20

To Find:

Focal length (f)

Explanation:

Formula:

\boxed{ \bold{\sf Focal \ length \ (f) = \frac{Radius \ of \ curvature \ (R)}{2}}}

Substituting value of R in the equation:

\sf \implies f =  \frac{20}{2}

\sf \implies f = \frac{ \cancel{2} \times 10}{ \cancel{2}}

\sf \implies f = 10 \: cm

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