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Lera25 [3.4K]
3 years ago
15

During the execution of a play, a football player carries the ball for a distance of 33 m in the direction 58° north of east. To

determine the number of meters gained on the play, find the northward component of the ball's displacement.
Physics
1 answer:
podryga [215]3 years ago
8 0

Answer:28 m

Explanation:

Given

Direction is 58^{\circ} North of east i.e. 58 ^{\circ} with x axis

Also ball moved by 33 m

therefore its east component is 33cos58=17.48 m

Northward component =33sin58=27.98 m\approx 28 m

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Answer:

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Solution:

According to the question:

Length of pipe, l = 1.75 m

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Frequency of first overtone, f_{1} is given by:

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4 0
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A person pushes on the handle of a lawnmower with a force of 280. n. if the handle makes an angle of 40.0 degrees with the groun
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<span>Force F = 280 N Angle with the ground = 40 degrees Weight of the Lawnmower = 350 N Velocity is constant so Acceleration is 0 So Forward force Ff = F cos theta = 280 cos40 Frictional force with resists to back Fb = (u x Force from pressure) + vertical component of Force, where u is the coefficient of friction. Fb = (u x m x g) + (u x 280sin40) AS Ff = Fb => 280 cos40 = u x ((m x g) + 280sin40) u = 280 cos40 / ((350 x 9.81) + 280sin40) = 214.49 / () = 0.405 So the coefficient of friction u = 0.405</span>
8 0
3 years ago
Read 2 more answers
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