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Nonamiya [84]
3 years ago
15

The difference of the square of a number and 16 is equal to 6 times that number. Find the negative solution.

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

The negative solution is -2

Step-by-step explanation:

Let the number be x

x² - 16 = 6x

Equate the equation to zero (0)

x² - 6x -16 = 0

Factorize

x² + 2x -8x - 16 = 0

x(x + 2) -8(x + 2) = 0

Therefore,

(x-8) (x +2) = 0

x -8 = 0         or           x +2 = 0

x = 8             or            x = -2

The negative solution is -2

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Answer:This problem is about linear equations. We assume Dale drive X miles, and the total cost is $Y, then we can get:

Plan I: Y=38+0.11X

Plan II: Y=49+0.07X

When both plans cost the same, 38+0.11X=49+0.07X. We will get X = 275miles, and Y=$68.25

Step-by-step explanation:

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2 years ago
Amanda canoed 15 3/4 miles in 3 hours. What was her average rate of speed in miles per hour?
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Answer:
5 1/4 miles per hour.

Explanation:

We first convert 15 3/4 to 15.75.

miles/hour

15.75/3 =5.25 miles per hour

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Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1
kompoz [17]

Question:

Simplify the radical expressions

1.\ \sqrt{63     2.\ \sqrt{48    3.\ \sqrt{75      4.\ \sqrt{99      5.\ \sqrt{92

6.\ \sqrt[3]{24}      7.\ \sqrt[3]{81}      8.\ \sqrt{128}     9.\sqrt[3]{40}     10.\ \sqrt[3]{135}

Answer:

\sqrt{63}= 3 \sqrt7

\sqrt{48} = 4\sqrt{3}

\sqrt{75} = 5\sqrt{3}

\sqrt{99} = 3 \sqrt{11

\sqrt{92} = 2\sqrt{23

\sqrt[3]{24} = 2 \sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

\sqrt{128} = 8 \sqrt{2}

\sqrt[3]{40} = 2 \sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

Step-by-step explanation:

1.\ \sqrt{63    

Express 63 as 9 * 7

\sqrt{63}= \sqrt{9 * 7

Split:

\sqrt{63}= \sqrt{9} * \sqrt7

\sqrt{63}= 3 * \sqrt7

\sqrt{63}= 3 \sqrt7

2.\ \sqrt{48    

Express 48 as 16 * 3

\sqrt{48} = \sqrt{16*3}

Split

\sqrt{48} = \sqrt{16}*\sqrt{3}

\sqrt{48} = 4*\sqrt{3}

\sqrt{48} = 4\sqrt{3}

3.\ \sqrt{75    

Express 75 as 25 * 3

\sqrt{75} = \sqrt{25*3}

Split

\sqrt{75} = \sqrt{25}*\sqrt{3}

\sqrt{75} = 5\sqrt{3}

4.\ \sqrt{99  

Express 99 as 9 * 11

\sqrt{99} = \sqrt{9} * \sqrt{11}

Split

\sqrt{99} = 3 \sqrt{11

5.\ \sqrt{92

Express 92 as 4 * 23

\sqrt{92} = \sqrt{4} * \sqrt{23

\sqrt{92} = 2* \sqrt{23

\sqrt{92} = 2\sqrt{23

6.\ \sqrt[3]{24}    

Express 24 as 8 * 3

\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}

Express 8 as 2^3

\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}

\sqrt[3]{24} = 2 \sqrt[3]{3}

7.\ \sqrt[3]{81}

Express 81 as 27 * 3

\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}

Express 27 as 3^3

\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}

\sqrt[3]{81} =3\sqrt[3]{3}

8.\ \sqrt{128}    

Express 128 as 64 * 2

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

9.\sqrt[3]{40}

Express 40 as 8 * 5

\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}

\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}

\sqrt[3]{40} = 2 \sqrt[3]{5}

10.\ \sqrt[3]{135}

Express 135 as 27 * 5

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

Express 27 as 3^3

\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}

\sqrt[3]{135} =3\sqrt[3]{5}

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kobusy [5.1K]

2 t + 2 (1 - 3 t)

= 2t + 2 - 6t     (distributive property)

= 2 - 4t            (combine like terms)

8 0
2 years ago
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Lorico [155]
The answer is C because when t=9, the equations are equal, but the expressions themselves are not equal to each other.
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2 years ago
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