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salantis [7]
3 years ago
9

Conteúdo: Cubo da soma e da diferença. Proposta: obs: com calculo por favor.

Mathematics
1 answer:
melomori [17]3 years ago
8 0

Answer:

Conteúdo: Cubo da soma e da diferença.

Proposta:

obs: com calculo por favor.

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Anyone know this one
Novosadov [1.4K]

Answer:

A e/f

Step-by-step explanation:

\frac{-e}{-f} = \frac{e}{f}

Two negatives always equal one positive

Recall:

Negative + Negative = Positive

Negative + Positive = Negative

Positive + Positive = Positive

5 0
4 years ago
Read 2 more answers
Helpp<br> hhhhhhhhhhhhhhhhhhhhhhhhhhhheeeeeeeeeeelllllllllpppppppp
____ [38]

Answer:

a goes with -1/2

b goes with -2

c goes with 2

d goes with -1/2

just multiply the x values of the top equation by the answers and you'll get the x values of the bottom equation :)

8 0
3 years ago
Lines l and m are parallel to one another and cut by and cut by transversals s and t
Lerok [7]

Answer:

you got parallel.  the one look like a x is insterseting  

Step-by-step explanation:

60+40=100

3 0
2 years ago
Find the smallest number by which 35280 must be multiplied so that the product is a perfect square.
nlexa [21]

5 is the <em>smallest</em> number by which 35280 must be multiplied so that the product will be a <em>perfect</em> square.

<h3>What number must be an integer multiplied by to find a perfect square? </h3>

A number is a <em>perfect</em> square if the following property is satisfied:

a = b², where is a <em>natural</em> number.

Please notice that b can be either a <em>prime</em> number or a product of <em>prime</em> numbers.

Initially, we proceed to factorize 35280 by factorial decomposition, that is, as a product of <em>prime</em> numbers:

35280 = 2⁴ × 3² × 5 × 7²

35280 = (2²)² × 3² × 5 × 7²

35280 = 4² × 3² × 5 × 7²

Then, we must add a 5 to find a product that is a perfect square:

4² × 3² × 5² × 7² = 176400

5 is the <em>smallest</em> number by which 35280 must be multiplied so that the product will be a <em>perfect</em> square.

To learn more on prime numbers: brainly.com/question/9315685

#SPJ1

5 0
2 years ago
What is wrong with this “proof”? “Theorem” For every positive integer n, if x and y are positive integers with max(x, y) = n, th
VMariaS [17]

The assumption of the inductive step is not correct. If \mathrm{max}(x,y)=2, for instance, it's entirely possible that x=1 and y=2.

3 0
4 years ago
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