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s344n2d4d5 [400]

3 years ago

8

How to put 26.23 in scientific notation

1 answer:

Maslowich3 years ago

6 0

The scientific notation is 2.623•10 to the power of one

The scientific e notation is 2.623e1

The decimal notation is 26.23

Hope this helps

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Log 3243<br><br> a)5<br> b)7<br> c)4<br> d)6

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Solve the inequality. Graph the solution.<br><br> w+6≤−3

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Step-by-step explanation:

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3. Write three ratios equal to 4/36

tia_tia [17]

${\Huge{\boxed{\mathbb{QUESTION}}}$

Write three ratios equal to $\frac{4}{36}$

${\huge{\boxed{\mathbb{EXPLANATION\:WITH\:REASONING\;}}}$

This ratio can be represented as $4:36$

_______________________________

${\Huge{\boxed{\mathbb{THE\:RATIOS}}}$

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${\huge{\boxed{\mathbb{TERMS}}}$

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3 years ago

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jolli1 [7]

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3 years ago

Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body

nika2105 [10]

Answer:

The position at time t is $s(t) = 8t^2 - 14t -8$

Step-by-step explanation:

From the question we are told that

The acceleration is $a = 16$

The velocity at t = 0 is $v(0) = -14$

The position at time t = 0 is $s(0) = -8$

Generally acceleration is mathematically represented as

$a(t) = \frac{d v}{dt }$

=> $\frac{dv}{dt} = 16$

=> $dv = 16 dt$

integrating both sides we have

$\int\limits dv = \int\limits16 dt$

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Now at t = 0

$v(0) = 16 * 0 +c = -14$

=> $c = -14$

So

$v(t) = 16 t -14$

Generally the position of the body is mathematically represented as

$s(t) = \int\limits v(t)dt$

So

$s(t) = \int\limits 16t - 14 dt$

So

$s(t) = 16 \frac{t^2}{2} - 14t + C$

Now at t = 0

$s(0) = 16 \frac{0^2}{2} - 14(0) + C = -8$

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So

$s(t) = 8t^2 - 14t -8$

5 0

3 years ago