I can answer this for you its 4.8,2.6,and 2.3
y-y1 = m (x-x1) y+3 = (1/4)(x+4) [using point (x1,y1)] or y–1 = (1/4)(x–12) [using point (x2,y2] [let's use this one since you did] To put this into Standard Form (Ax+By=C), y–1 = (1/4)(x–12) 4y - 4 = x - 12 -x + 4y - 4 = -12 [subtract x from both sides] -x + 4y = -8 [add 4 to both sides] x - 4y = 8 [multiply by (-1) to have x-coefficient positive
Answer:
1.12 × 10^-3
Step-by-step explanation:
The computation of the width of the photograph is as follows:
As we know that
Area of the rectangle = length × width
33 ÷ 20 square inches = 1475 inches × width
So, the width is
= Length ÷ area
= 1475 inches ÷ (33 ÷ 20 square inches)
= 1.12 × 10^-3
10×4,000=40,000 because all u do is add an extra zero everything you multiple something by ten
Answer:
66
Step-by-step explanation:
4^3=64
64+2(3-2)
64+6-4 =64+2.
64+2=66
