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2 years ago

15

Propiedades quimicas de la plata

1 answer:

timofeeve [1]2 years ago

7 0

Elemento químico, símbolo Ag, número atómico 47 y masa atómica 107.870. Es un metal lustroso de color blanco-grisáceo. La plata, que posee las más altas conductividades térmica y eléctrica de todos los metales, se utiliza en puntos de contacto eléctricos y electrónicos.

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stepladder [879]

This must be your work, otherwise it's against the Brainly code of conduct. If you need help finding a newspaper, go to BBC. They have plenty of relevant articles.

4 0

1 year ago

The decomposition of mercury (ii) oxide at high temperature, is it an endothermic or exothermic process? Write a chemical reacti

gulaghasi [49]

Answer:

that will be endothermic reaction...... as oxides of mercury decomposes and break s into simpler elements by absorbing energy

Explanation:

hope it helped u buddy

6 0

2 years ago

Read 2 more answers

The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?

Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0

3 years ago

Which of the following methods will usually cause a reaction to speed up?

maw [93]

Reducing the concentration of reactants

5 0

2 years ago

The density of air under ordinary conditions at 25°C is 1.19 g/L. How many kilograms of air are in a room that measures 10.0 ft

Lunna [17]

Answer: The mass of air present in the room is 37.068 kg

Explanation : Given,

Length of the room = 10.0 ft

Breadth of the room = 11.0 ft

Height of the room = 10.0 ft

To calculate the volume of the room by using the formula of volume of cuboid, we use the equation:

$V=lbh$

where,

V = volume of the room

l = length of the room

b = breadth of the room

h = height of of the room

Putting values in above equation, we get:

$V=10.0ft\times 11.0ft\times 10.0ft=1100ft^3=31148.53L$

Conversion used : $1ft^3=28.3168L$

Now we have to calculate the mass of air in the room.

$Density=\frac{Mass}{Volume}$

$1.19g/L=\frac{Mass}{31148.53L}$

$Mass=37066.7507g=37.068kg$

Conversion used : (1 kg = 1000 g)

Therefore, the mass of air present in the room is 37.068 kg

3 0

2 years ago

Read 2 more answers