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BARSIC [14]
3 years ago
7

Is 0, 125 a termatingdecimal?

Mathematics
1 answer:
blagie [28]3 years ago
5 0
Yes it is ,I need extra letters sorry but gdyhfdujbbccccccgh
You might be interested in
Find the Area of the Shaded Region.
agasfer [191]

Answer:

I think it should be 32

Step-by-step explanation:

11 x 7= 77

9 x 5=45

77-45=32

3 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each verbal description of a sequen
galben [10]

Answer:

I think the question is wrong so, I will try and explain with some right questions

Step-by-step explanation:

We are give 6 sequences to analyse

1. an = 3 · (4)n - 1

2. an = 4 · (2)n - 1

3. an = 2 · (3)n - 1

4. an = 4 + 2(n - 1)

5. an = 2 + 3(n - 1)

6. an = 3 + 4(n - 1)

1. This is the correct sequence

an=3•(4)^(n-1)

If this is an

Let know an+1, the next term

an+1=3•(4)^(n+1-1)

an+1=3•(4)^n

There fore

Common ratio an+1/an

r= 3•(4)^n/3•(4)^n-1

r= (4)^(n-n+1)

r=4^1

r= 4, then the common ratio is 4

Then

First term is when n=1

an=3•(4)^(n-1)

a1=3•(4)^(1-1)

a1=3•(4)^0=3.4^0

a1=3

The first term is 3 and the common ratio is 4, it is a G.P

2. This is the correct sequence

an=4•(2)^(n-1)

Therefore, let find an+1

an+1=4•(2)^(n+1-1)

an+1= 4•2ⁿ

Common ratio=an+1/an

r=4•2ⁿ/4•(2)^(n-1)

r=2^(n-n+1)

r=2¹=2

Then the common ratio is 2,

The first term is when n =1

an=4•(2)^(n-1)

a1=4•(2)^(1-1)

a1=4•(2)^0

a1=4

It is geometric progression with first term 4 and common ratio 2.

3. This is the correct sequence

an=2•(3)^(n-1)

Therefore, let find an+1

an+1=2•(3)^(n+1-1)

an+1= 2•3ⁿ

Common ratio=an+1/an

r=2•3ⁿ/2•(3)^(n-1)

r=3^(n-n+1)

r=3¹=3

Then the common ratio is 3,

The first term is when n =1

an=2•(3)^(n-1)

a1=2•(3)^(1-1)

a1=2•(3)^0

a1=2

It is geometric progression with first term 2 and common ratio 3.

4. I think this correct sequence so we will use it.

an = 4 + 2(n - 1)

Let find an+1

an+1= 4+2(n+1-1)

an+1= 4+2n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=4+2n-(4+2(n-1))

d=4+2n-4-2(n-1)

d=4+2n-4-2n+2

d=2.

The common difference is 2

Now, the first term is when n=1

an=4+2(n-1)

a1=4+2(1-1)

a1=4+2(0)

a1=4

This is an arithmetic progression of common difference 2 and first term 4.

5. I think this correct sequence so we will use it.

an = 2 + 3(n - 1)

Let find an+1

an+1= 2+3(n+1-1)

an+1= 2+3n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=2+3n-(2+3(n-1))

d=2+3n-2-3(n-1)

d=2+3n-2-3n+3

d=3.

The common difference is 3

Now, the first term is when n=1

an=2+3(n-1)

a1=2+3(1-1)

a1=2+3(0)

a1=2

This is an arithmetic progression of common difference 3 and first term 2.

6. I think this correct sequence so we will use it.

an = 3 + 4(n - 1)

Let find an+1

an+1= 3+4(n+1-1)

an+1= 3+4n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=3+4n-(3+4(n-1))

d=3+4n-3-4(n-1)

d=3+4n-3-4n+4

d=4.

The common difference is 4

Now, the first term is when n=1

an=3+4(n-1)

a1=3+4(1-1)

a1=3+4(0)

a1=3

This is an arithmetic progression of common difference 4 and first term 3.

5 0
3 years ago
Adding, Subtracting, Multiplying, and Dividing Rationals and Solving Equations with Rationals in a real world scenario?
eduard

Answer:

cnc machining can include a lot of maths in it

4 0
3 years ago
The image shows three tennis balls enclosed in a cylindrical can. Choose all that are correct. The volume of a single tennis bal
Fynjy0 [20]

Answer:

The volume of a single tennis ball is 14.14\ in^{3}

The volume of three tennis balls is 42.42\ in^{3}

Step-by-step explanation:

Step 1

Find the volume of a single tennis ball

we know that

The volume of a sphere is equal to

V=\frac{4}{3}\pi r^{3}

where r is the radius of the sphere

In this problem

r=3/2=1.5\ in

substitute

V=\frac{4}{3}\pi (1.5)^{3}

V=14.14\ in^{3}

Step 2

Find the volume of the can

we know that

the volume of the cylinder is equal to

V=\pi r^{2} h

where r is the radius of the cylinder

h is the height of the cylinder

in this problem we have

r=3/2=1.5\ in

h=8.4\ in

substitute

V=\pi (1.5)^{2}(8.4)

V=59.38\ in^{3}

Statement

<u>case A)</u> The volume of a single tennis ball is 14.14\ in^{3}

The statement is true

See the procedure in Step 1

<u>case B)</u> The volume of the can is 56.55\ in^{3}

The statement is false

The volume of the can is 59.38\ in^{3} --> see the procedure Step 2

<u>case C)</u> The empty space inside the can is 14.13\ in^{3}

The statement is false

To find the empty space subtract the volume of three tennis ball from the volume of the can

59.38\ in^{3}-3*14.14\ in^{3}=16.96\ in^{3}

<u>case D)</u> The volume of three tennis balls is 42.42\ in^{3}

The statement is true

To find the volume of three tennis balls multiply the volume of a single tennis ball by three

14.14*3=42.42\ in^{3}

8 0
3 years ago
Brandon sold at least 168 tickets for a carnival. He sold 4 more adult tickets than children tickets.
iris [78.8K]

Answer:

80

Step-by-step explanation:

6 0
3 years ago
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